手机号码将由用户在我的 Android 应用程序的注册页面上的编辑文本中输入。我如何检查用户输入的是他/她的手机号码而不是其他人的?
我已经试过了:
TelephonyManager tMgr =(TelephonyManager)mAppContext.getSystemService(Context.TELEPHONY_SERVICE);
mPhoneNumber = tMgr.getLine1Number();
并将此变量与 edittext 的文本进行比较。但在我的例子中,mPhoneNumber 返回 NULL。还有其他选择吗?如何解决这个问题?
任何帮助都将不胜感激。
我试过这个:检查源代码:
public class MainActivity extends Activity{
Button submit;
EditText contact;
String phNo;
ProgressDialog progress;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
contact = (EditText)findViewById(R.id.mobileNumber);
submit = (Button) findViewById(R.id.button1);
submit.setOnClickListener(new OnClickListener()
{
public void onClick(View v)
{
phNo = contact.getText().toString();
new CheckOwnMobileNumber().execute();
Toast.makeText(getApplicationContext(), phNo, Toast.LENGTH_LONG).show();
}
});
}
private class CheckOwnMobileNumber extends AsyncTask<String, Void, String>
{
@Override
protected void onPostExecute(String result)
{
// TODO Auto-generated method stub
if(progress.isShowing())
{
progress.dismiss();
// Check SMS Received or not after that open dialog date
/*if(SMSReceiver.str.equals(phNo))
{
Toast.makeText(getApplicationContext(), "Thanks for providing your number.", Toast.LENGTH_LONG).show();
}
else
{
Toast.makeText(getApplicationContext(), "Provide your own mobile number please.", Toast.LENGTH_LONG).show();
return;
}*/
}
}
@Override
protected String doInBackground(String... params)
{
// TODO Auto-generated method stub
String msg = phNo;
try
{
sendSMS(phNo, msg);
}
catch(Exception ex)
{
Log.v("Exception :", ""+ex);
}
return null;
}
@Override
protected void onPreExecute() {
// TODO Auto-generated method stub
progress = ProgressDialog.show(MainActivity.this, "","Checking Mobile Number...");
progress.setIndeterminate(true);
progress.getWindow().setLayout(LayoutParams.WRAP_CONTENT,LayoutParams.WRAP_CONTENT);
super.onPreExecute();
}
}
private void sendSMS(String phoneNumber, String message)
{
//PendingIntent pi = PendingIntent.getActivity(getApplicationContext(), 0, new Intent(getApplicationContext(), MainActivity.class), 0);
SmsManager sms = SmsManager.getDefault();
sms.sendTextMessage(phoneNumber, null, message, null, null);
}
}
接收者是否收听短信?
public class SMSReceiver extends BroadcastReceiver
{
private static final String ACTION_SMS_RECEIVED = "android.provider.Telephony.SMS_RECEIVED";
Context mContext;
private Intent mIntent;
static String address, str = null;
// Retrieve SMS
public void onReceive(Context context, Intent intent) {
mContext = context;
mIntent = intent;
String action = intent.getAction();
if(action.equals(ACTION_SMS_RECEIVED))
{
SmsMessage[] msgs = getMessagesFromIntent(mIntent);
if (msgs != null)
{
for (int i = 0; i < msgs.length; i++)
{
address = msgs[i].getOriginatingAddress();
str = msgs[i].getMessageBody().toString();
}
}
// ---send a broadcast intent to update the SMS received in the
// activity---
Intent broadcastIntent = new Intent();
broadcastIntent.setAction("SMS_RECEIVED_ACTION");
broadcastIntent.putExtra("sms", str);
context.sendBroadcast(broadcastIntent);
}
}
public static SmsMessage[] getMessagesFromIntent(Intent intent)
{
Object[] messages = (Object[]) intent.getSerializableExtra("pdus");
byte[][] pduObjs = new byte[messages.length][];
for (int i = 0; i < messages.length; i++)
{
pduObjs[i] = (byte[]) messages[i];
}
byte[][] pdus = new byte[pduObjs.length][];
int pduCount = pdus.length;
SmsMessage[] msgs = new SmsMessage[pduCount];
for (int i = 0; i < pduCount; i++)
{
pdus[i] = pduObjs[i];
msgs[i] = SmsMessage.createFromPdu(pdus[i]);
}
return msgs;
}
}
洛卡特:
03-13 17:31:02.049: E/ActivityManager(161): ANR in com.example.test
03-13 17:31:02.049: E/ActivityManager(161): Reason: Broadcast of Intent { act=android.provider.Telephony.SMS_RECEIVED cmp=com.example.test/.SMSReceiver (has extras) }
03-13 17:31:02.049: E/ActivityManager(161): 54% 3732/com.example.test: 54% user + 0% kernel / faults: 21 minor
03-13 17:31:02.049: E/ActivityManager(161): 40% 3732/com.example.test: 40% user + 0% kernel / faults: 2 minor
03-13 17:31:30.699: I/ActivityManager(161): Killing com.example.test (pid=3732): user's request
03-13 17:31:30.799: I/ActivityManager(161): Process com.example.test (pid 3732) has died.
03-13 17:31:30.799: I/WindowManager(161): WIN DEATH: Window{40992f50 com.example.test/com.example.test.MainActivity paused=false}
03-13 17:31:30.819: E/InputDispatcher(161): channel '40818670 com.example.test/com.example.test.MainActivity (server)' ~ Consumer closed input channel or an error occurred. events=0x8
03-13 17:31:30.819: E/InputDispatcher(161): channel '40818670 com.example.test/com.example.test.MainActivity (server)' ~ Channel is unrecoverably broken and will be disposed!
03-13 17:34:59.649: I/ActivityManager(161): Start proc com.example.test for broadcast com.example.test/.SMSReceiver: pid=4037 uid=10098 gids={}
最佳答案
不能保证 tMgr.getLine1Number();
将始终返回您的 SIM 卡号码。因为这取决于 SIM 卡中号码的可用性。就像我的情况一样,我的 Tre-Sweden SIM 卡不包含我的电话号码。
但是如果您将 SIM 卡放入旧的 SonyEricsson 或诺基亚手机中,那么您将可以选择编辑此号码(在 SIM 上)。完成后,Android 设备将识别该号码并显示给您。
此外,如果你确实是通过验证码获取到你的电话号码,那么比较两个号码的最佳方式是:
boolean isSame = PhoneNumberUtils.compare(num1, num2);
或者,您可以实现某种 PIN 码验证逻辑(例如 Viber、WhatsApp 或其他应用程序),您可以在其中要求用户在注册期间输入他们的电话号码。稍后,该电话号码会被发送到服务器,并根据该号码生成一个 PIN 码,并通过 SMS 发送给用户。最后,用户必须输入该 PIN 码(通过短信收到)才能完成注册。
或者
只需从用户的设备(在征得同意的情况下)向您的服务器/设备发送一条短信,即可了解他们的电话号码。
关于android - 如何检查用户在 EditText 中输入自己的电话号码?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15019582/