我希望此函数返回 ajax 调用是否成功。我有什么办法可以做到这一点吗?我下面的代码不会执行此操作。
function myFunction(data) {
var result = false;
$.ajax({
type: "POST",
contentType: "application/json",
dataType: "json",
url: "url",
data: data,
error: function(data){
result = false;
return false;
},
success: function(data){
result = true;
return true;
}
});
return result;
}
最佳答案
不幸的是,您无法将值返回给包装异步回调的函数。相反,来自 AJAX 请求的成功回调会将数据和控制权移交给另一个函数。我在下面演示了这个概念:
myFunction 的定义:
// I added a second parameter called "callback", which takes a function
// as a first class object
function myFunction(data, callback) {
var result = false;
$.ajax({
type: "POST",
contentType: "application/json",
dataType: "json",
url: "url",
data: data,
error: function(data){
result = false;
// invoke the callback function here
if(callback != null) {
callback(result);
}
// this would return to the error handler, which does nothing
//return false;
},
success: function(data){
result = true;
// invoke your callback function here
if(callback != null) {
callback(result);
}
// this would actually return to the success handler, which does
// nothing as it doesn't assign the value to anything
// return true;
}
});
// return result; // result would be false here still
}
回调函数定义:
// this is the definition for the function that takes the data from your
// AJAX success handler
function processData(result) {
// do stuff with the result here
}
调用您的 myFunction:
var data = { key: "value" }; /* some object you're passing in */
// pass in both the data as well as the processData function object
// in JavaScript, functions can be passed into parameters as arguments!
myFunction(data, processData);
关于jquery - JQuery ajax调用的返回值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10768991/