javascript - 计算Javascript中两个日期之间的工作日(节假日除外)

Question

我有一个 JavaScript 函数，它可以计算两个日期之间的工作日，它可以工作，但问题是它不考虑假期。如何修改此函数，例如通过在异常数组中添加假期？

在网上搜索了这个问题，但没有找到有关假期异常(exception)的信息。

例如假期数组:

var holidays = ['2016-05-03','2016-05-05'];

我有一个函数来计算这个:

function workingDaysBetweenDates(d0, d1) {
    var startDate = parseDate(d0);
    var endDate = parseDate(d1);  
    // Validate input
    if (endDate < startDate)
        return 0;

    // Calculate days between dates
    var millisecondsPerDay = 86400 * 1000; // Day in milliseconds
    startDate.setHours(0,0,0,1);  // Start just after midnight
    endDate.setHours(23,59,59,999);  // End just before midnight
    var diff = endDate - startDate;  // Milliseconds between datetime objects    
    var days = Math.ceil(diff / millisecondsPerDay);

    // Subtract two weekend days for every week in between
    var weeks = Math.floor(days / 7);
    days = days - (weeks * 2);

    // Handle special cases
    var startDay = startDate.getDay();
    var endDay = endDate.getDay();

    // Remove weekend not previously removed.   
    if (startDay - endDay > 1)         
        days = days - 2;      

    // Remove start day if span starts on Sunday but ends before Saturday
    if (startDay == 0 && endDay != 6)
        days = days - 1  

    // Remove end day if span ends on Saturday but starts after Sunday
    if (endDay == 6 && startDay != 0)
        days = days - 1  

    return days;
}
function parseDate(input) {
    // Transform date from text to date
  var parts = input.match(/(\d+)/g);
  // new Date(year, month [, date [, hours[, minutes[, seconds[, ms]]]]])
  return new Date(parts[0], parts[1]-1, parts[2]); // months are 0-based
}

在jsfiddle中做了一个例子:

JSFiddle example

也许还有一些其他函数可以在 Jquery 中轻松使用？

Answer 1

尝试:

var startDate = new Date('05/03/2016');
var endDate = new Date('05/10/2016');
var numOfDates = getBusinessDatesCount(startDate,endDate);

function getBusinessDatesCount(startDate, endDate) {
    let count = 0;
    const curDate = new Date(startDate.getTime());
    while (curDate <= endDate) {
        const dayOfWeek = curDate.getDay();
        if(dayOfWeek !== 0 && dayOfWeek !== 6) count++;
        curDate.setDate(curDate.getDate() + 1);
    }
    alert(count);
    return count;
}