我使用 this bl.ocks.org code example 创建了一个多系列折线图。我已成功在 JSFiddle 上重新创建它.
现在，我尝试添加一个 x 值鼠标悬停工具提示，当您将鼠标悬停在其垂直位置时，它会在每行显示一个工具提示。类似于 this ，但适用于多行。
我找到了this StackOverflow answer (它包括 JSFiddle )，但我似乎无法使其与我的多系列折线图一起使用。
svg.append("path") // this is the black vertical line to follow mouse
.attr("class","mouseLine")
.style("stroke","black")
.style("stroke-width", "1px")
.style("opacity", "0");
var mouseCircle = causation.append("g") // for each line, add group to hold text and circle
.attr("class","mouseCircle");
mouseCircle.append("circle") // add a circle to follow along path
.attr("r", 7)
.style("stroke", function(d) { console.log(d); return color(d.key); })
.style("fill","none")
.style("stroke-width", "1px");
mouseCircle.append("text")
.attr("transform", "translate(10,3)"); // text to hold coordinates
var bisect = d3.bisector(function(d) { return d.YEAR; }).right; // reusable bisect to find points before/after line
svg.append('svg:rect') // append a rect to catch mouse movements on canvas
.attr('width', width) // can't catch mouse events on a g element
.attr('height', height)
.attr('fill', 'none')
.attr('pointer-events', 'all')
.on('mouseout', function(){ // on mouse out hide line, circles and text
d3.select(".mouseLine")
.style("opacity", "0");
d3.selectAll(".mouseCircle circle")
.style("opacity", "0");
d3.selectAll(".mouseCircle text")
.style("opacity", "0");
})
.on('mouseover', function(){ // on mouse in show line, circles and text
d3.select(".mouseLine")
.style("opacity", "1");
d3.selectAll(".mouseCircle circle")
.style("opacity", "1");
d3.selectAll(".mouseCircle text")
.style("opacity", "1");
})
.on('mousemove', function() { // mouse moving over canvas
d3.select(".mouseLine")
.attr("d", function(){
yRange = y.range(); // range of y axis
var xCoor = d3.mouse(this)[0]; // mouse position in x
var xDate = x.invert(xCoor); // date corresponding to mouse x
d3.selectAll('.mouseCircle') // for each circle group
.each(function(d,i){
var rightIdx = bisect(data[1].values, xDate); // find date in data that right off mouse
var interSect = get_line_intersection(xCoor, // get the intersection of our vertical line and the data line
yRange[0],
xCoor,
yRange[1],
x(data[i].values[rightIdx-1].YEAR),
y(data[i].values[rightIdx-1].VALUE),
x(data[i].values[rightIdx].YEAR),
y(data[i].values[rightIdx].VALUE));
d3.select(this) // move the circle to intersection
.attr('transform', 'translate(' + interSect.x + ',' + interSect.y + ')');
d3.select(this.children[1]) // write coordinates out
.text(xDate.toLocaleDateString() + "," + y.invert(interSect.y).toFixed(0));
});
return "M"+ xCoor +"," + yRange[0] + "L" + xCoor + "," + yRange[1]; // position vertical line
});
});
// from here: https://stackoverflow.com/a/1968345/16363
function get_line_intersection(p0_x, p0_y, p1_x, p1_y,
p2_x, p2_y, p3_x, p3_y)
{
var rV = {};
var s1_x, s1_y, s2_x, s2_y;
s1_x = p1_x - p0_x; s1_y = p1_y - p0_y;
s2_x = p3_x - p2_x; s2_y = p3_y - p2_y;
var s, t;
s = (-s1_y * (p0_x - p2_x) + s1_x * (p0_y - p2_y)) / (-s2_x * s1_y + s1_x * s2_y);
t = ( s2_x * (p0_y - p2_y) - s2_y * (p0_x - p2_x)) / (-s2_x * s1_y + s1_x * s2_y);
if (s >= 0 && s <= 1 && t >= 0 && t <= 1)
{
// Collision detected
rV.x = p0_x + (t * s1_x);
rV.y = p0_y + (t * s1_y);
}
return rV;
}
所以，简单来说，我想结合我的line chart JSFiddle有了这个tooltip JSFiddle 。有人知道怎么做这个吗？或者有没有更简单的方法来创建这样的工具提示？如有任何帮助，我们将不胜感激!
最佳答案
您提到的问题我在四月份回答过。从那时起，我对 SVG 和 d3 有了更多了解，因此我将将此作为该答案的更新。
注意，我从 @Duopixel 的优秀代码示例 here 借用了一些代码。
以下是评论详情:
// append a g for all the mouse over nonsense
var mouseG = svg.append("g")
.attr("class", "mouse-over-effects");
// this is the vertical line
mouseG.append("path")
.attr("class", "mouse-line")
.style("stroke", "black")
.style("stroke-width", "1px")
.style("opacity", "0");
// keep a reference to all our lines
var lines = document.getElementsByClassName('line');
// here's a g for each circle and text on the line
var mousePerLine = mouseG.selectAll('.mouse-per-line')
.data(cities)
.enter()
.append("g")
.attr("class", "mouse-per-line");
// the circle
mousePerLine.append("circle")
.attr("r", 7)
.style("stroke", function(d) {
return color(d.name);
})
.style("fill", "none")
.style("stroke-width", "1px")
.style("opacity", "0");
// the text
mousePerLine.append("text")
.attr("transform", "translate(10,3)");
// rect to capture mouse movements
mouseG.append('svg:rect')
.attr('width', width)
.attr('height', height)
.attr('fill', 'none')
.attr('pointer-events', 'all')
.on('mouseout', function() { // on mouse out hide line, circles and text
d3.select(".mouse-line")
.style("opacity", "0");
d3.selectAll(".mouse-per-line circle")
.style("opacity", "0");
d3.selectAll(".mouse-per-line text")
.style("opacity", "0");
})
.on('mouseover', function() { // on mouse in show line, circles and text
d3.select(".mouse-line")
.style("opacity", "1");
d3.selectAll(".mouse-per-line circle")
.style("opacity", "1");
d3.selectAll(".mouse-per-line text")
.style("opacity", "1");
})
.on('mousemove', function() { // mouse moving over canvas
var mouse = d3.mouse(this);
// move the vertical line
d3.select(".mouse-line")
.attr("d", function() {
var d = "M" + mouse[0] + "," + height;
d += " " + mouse[0] + "," + 0;
return d;
});
// position the circle and text
d3.selectAll(".mouse-per-line")
.attr("transform", function(d, i) {
console.log(width/mouse[0])
var xDate = x.invert(mouse[0]),
bisect = d3.bisector(function(d) { return d.date; }).right;
idx = bisect(d.values, xDate);
// since we are use curve fitting we can't relay on finding the points like I had done in my last answer
// this conducts a search using some SVG path functions
// to find the correct position on the line
// from http://bl.ocks.org/duopixel/3824661
var beginning = 0,
end = lines[i].getTotalLength(),
target = null;
while (true){
target = Math.floor((beginning + end) / 2);
pos = lines[i].getPointAtLength(target);
if ((target === end || target === beginning) && pos.x !== mouse[0]) {
break;
}
if (pos.x > mouse[0]) end = target;
else if (pos.x < mouse[0]) beginning = target;
else break; //position found
}
// update the text with y value
d3.select(this).select('text')
.text(y.invert(pos.y).toFixed(2));
// return position
return "translate(" + mouse[0] + "," + pos.y +")";
});
});
完整的工作代码:
<!DOCTYPE html>
<html>
<head>
<script data-require="d3@3.5.3" data-semver="3.5.3" src="//cdnjs.cloudflare.com/ajax/libs/d3/3.5.3/d3.js"></script>
<style>
body {
font: 10px sans-serif;
}
.axis path,
.axis line {
fill: none;
stroke: #000;
shape-rendering: crispEdges;
}
.x.axis path {
display: none;
}
.line {
fill: none;
stroke: steelblue;
stroke-width: 1.5px;
}
</style>
</head>
<body>
<script>
var myData = "date New York San Francisco Austin\n\
20111001 63.4 62.7 72.2\n\
20111002 58.0 59.9 67.7\n\
20111003 53.3 59.1 69.4\n\
20111004 55.7 58.8 68.0\n\
20111005 64.2 58.7 72.4\n\
20111006 58.8 57.0 77.0\n\
20111007 57.9 56.7 82.3\n\
20111008 61.8 56.8 78.9\n\
20111009 69.3 56.7 68.8\n\
20111010 71.2 60.1 68.7\n\
20111011 68.7 61.1 70.3\n\
20111012 61.8 61.5 75.3\n\
20111013 63.0 64.3 76.6\n\
20111014 66.9 67.1 66.6\n\
20111015 61.7 64.6 68.0\n\
20111016 61.8 61.6 70.6\n\
20111017 62.8 61.1 71.1\n\
20111018 60.8 59.2 70.0\n\
20111019 62.1 58.9 61.6\n\
20111020 65.1 57.2 57.4\n\
20111021 55.6 56.4 64.3\n\
20111022 54.4 60.7 72.4\n";
var margin = {
top: 20,
right: 80,
bottom: 30,
left: 50
},
width = 500 - margin.left - margin.right,
height = 500 - margin.top - margin.bottom;
var parseDate = d3.time.format("%Y%m%d").parse;
var x = d3.time.scale()
.range([0, width]);
var y = d3.scale.linear()
.range([height, 0]);
var color = d3.scale.category10();
var xAxis = d3.svg.axis()
.scale(x)
.orient("bottom");
var yAxis = d3.svg.axis()
.scale(y)
.orient("left");
var line = d3.svg.line()
.interpolate("basis")
.x(function(d) {
return x(d.date);
})
.y(function(d) {
return y(d.temperature);
});
var svg = d3.select("body").append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
var data = d3.tsv.parse(myData);
color.domain(d3.keys(data[0]).filter(function(key) {
return key !== "date";
}));
data.forEach(function(d) {
d.date = parseDate(d.date);
});
var cities = color.domain().map(function(name) {
return {
name: name,
values: data.map(function(d) {
return {
date: d.date,
temperature: +d[name]
};
})
};
});
x.domain(d3.extent(data, function(d) {
return d.date;
}));
y.domain([
d3.min(cities, function(c) {
return d3.min(c.values, function(v) {
return v.temperature;
});
}),
d3.max(cities, function(c) {
return d3.max(c.values, function(v) {
return v.temperature;
});
})
]);
var legend = svg.selectAll('g')
.data(cities)
.enter()
.append('g')
.attr('class', 'legend');
legend.append('rect')
.attr('x', width - 20)
.attr('y', function(d, i) {
return i * 20;
})
.attr('width', 10)
.attr('height', 10)
.style('fill', function(d) {
return color(d.name);
});
legend.append('text')
.attr('x', width - 8)
.attr('y', function(d, i) {
return (i * 20) + 9;
})
.text(function(d) {
return d.name;
});
svg.append("g")
.attr("class", "x axis")
.attr("transform", "translate(0," + height + ")")
.call(xAxis);
svg.append("g")
.attr("class", "y axis")
.call(yAxis)
.append("text")
.attr("transform", "rotate(-90)")
.attr("y", 6)
.attr("dy", ".71em")
.style("text-anchor", "end")
.text("Temperature (ºF)");
var city = svg.selectAll(".city")
.data(cities)
.enter().append("g")
.attr("class", "city");
city.append("path")
.attr("class", "line")
.attr("d", function(d) {
return line(d.values);
})
.style("stroke", function(d) {
return color(d.name);
});
city.append("text")
.datum(function(d) {
return {
name: d.name,
value: d.values[d.values.length - 1]
};
})
.attr("transform", function(d) {
return "translate(" + x(d.value.date) + "," + y(d.value.temperature) + ")";
})
.attr("x", 3)
.attr("dy", ".35em")
.text(function(d) {
return d.name;
});
var mouseG = svg.append("g")
.attr("class", "mouse-over-effects");
mouseG.append("path") // this is the black vertical line to follow mouse
.attr("class", "mouse-line")
.style("stroke", "black")
.style("stroke-width", "1px")
.style("opacity", "0");
var lines = document.getElementsByClassName('line');
var mousePerLine = mouseG.selectAll('.mouse-per-line')
.data(cities)
.enter()
.append("g")
.attr("class", "mouse-per-line");
mousePerLine.append("circle")
.attr("r", 7)
.style("stroke", function(d) {
return color(d.name);
})
.style("fill", "none")
.style("stroke-width", "1px")
.style("opacity", "0");
mousePerLine.append("text")
.attr("transform", "translate(10,3)");
mouseG.append('svg:rect') // append a rect to catch mouse movements on canvas
.attr('width', width) // can't catch mouse events on a g element
.attr('height', height)
.attr('fill', 'none')
.attr('pointer-events', 'all')
.on('mouseout', function() { // on mouse out hide line, circles and text
d3.select(".mouse-line")
.style("opacity", "0");
d3.selectAll(".mouse-per-line circle")
.style("opacity", "0");
d3.selectAll(".mouse-per-line text")
.style("opacity", "0");
})
.on('mouseover', function() { // on mouse in show line, circles and text
d3.select(".mouse-line")
.style("opacity", "1");
d3.selectAll(".mouse-per-line circle")
.style("opacity", "1");
d3.selectAll(".mouse-per-line text")
.style("opacity", "1");
})
.on('mousemove', function() { // mouse moving over canvas
var mouse = d3.mouse(this);
d3.select(".mouse-line")
.attr("d", function() {
var d = "M" + mouse[0] + "," + height;
d += " " + mouse[0] + "," + 0;
return d;
});
d3.selectAll(".mouse-per-line")
.attr("transform", function(d, i) {
console.log(width/mouse[0])
var xDate = x.invert(mouse[0]),
bisect = d3.bisector(function(d) { return d.date; }).right;
idx = bisect(d.values, xDate);
var beginning = 0,
end = lines[i].getTotalLength(),
target = null;
while (true){
target = Math.floor((beginning + end) / 2);
pos = lines[i].getPointAtLength(target);
if ((target === end || target === beginning) && pos.x !== mouse[0]) {
break;
}
if (pos.x > mouse[0]) end = target;
else if (pos.x < mouse[0]) beginning = target;
else break; //position found
}
d3.select(this).select('text')
.text(y.invert(pos.y).toFixed(2));
return "translate(" + mouse[0] + "," + pos.y +")";
});
});
</script>
</body>
</html>关于jquery - 带有鼠标悬停工具提示的多系列折线图，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/34886070/