我手动创建了动态链接,并在链接上设置了一些附加参数,如下所示:https://XXXXX.goo.gl/?link=https%3A%2F%2Fairbanq.send.com%2Fsendmoney&apn=com.xxxx.xxxx&amv=1&username=Adri&amount=7.00
但是当应用程序打开时,我只得到:“https://airbanq.send.com/sendmoney” 没有额外的参数
我正在使用这个示例代码 https://github.com/firebase/quickstart-android/tree/master/dynamiclinks
请帮忙,
谢谢
我的代码
public String buildDeepLink() {
// Get the unique appcode for this app.
String appCode = AirBanqApp.mContext.getString(R.string.app_code);
// Get this app's package name.
String packageName = AirBanqApp.mContext.getPackageName();
// Build the link with all required parameters
Uri.Builder builder = new Uri.Builder()
.scheme("https")
.authority(appCode + ".app.goo.gl")
.path("/")
.appendQueryParameter("link", deepLink)
.appendQueryParameter("apn", packageName);
// If the deep link is used in an advertisement, this value must be set to 1.
if (isAd) {
builder.appendQueryParameter("ad", "1");
}
// Minimum version is optional.
if (minVersion > 0) {
builder.appendQueryParameter("amv", Integer.toString(minVersion));
}
if (!TextUtils.isEmpty(androidLink)) {
builder.appendQueryParameter("al", androidLink);
}
if (!TextUtils.isEmpty(playStoreAppLink)) {
builder.appendQueryParameter("afl", playStoreAppLink);
}
if (!customParameters.isEmpty()) {
for (Map.Entry<String, String> parameter : customParameters.entrySet()) {
builder.appendQueryParameter(parameter.getKey(), parameter.getValue());
}
}
// Return the completed deep link.
return builder.build().toString();
}
最佳答案
这就是我的解决方案
我解决了我的问题,我假设“apn”、“用户名”和“数量”是 url 中参数“LINK”的一部分,但是当我添加“&”时没有,我正在向主 url,要将参数添加到“LINK”字段,我需要先创建这样的 url
https://airbanq.send.com/sendmoney?username=Adri&amount=7.00
然后使用 URLEncoder.encode(queryParameters.toString(), "UTF-8"); 生成这个 https%3A%2F%2Fairbanq.send.com%2Fsendmoney%253Fusername%253DAdri%2526amount%253D7.00
然后附加到主 url
public String buildDeepLink() {
// Get the unique appcode for this app.
String appCode = AirBanqApp.mContext.getString(R.string.app_code);
// Get this app's package name.
String packageName = AirBanqApp.mContext.getPackageName();
String queryParamters = "";
try {
queryParamters = generateQueryParameters();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
if (!TextUtils.isEmpty(queryParamters)) {
deepLink = deepLink + queryParamters;
}
// Build the link with all required parameters
Uri.Builder builder = new Uri.Builder()
.scheme("https")
.authority(appCode + ".app.goo.gl")
.path("/")
.appendQueryParameter("link", deepLink)
.appendQueryParameter("apn", packageName);
// If the deep link is used in an advertisement, this value must be set to 1.
if (isAd) {
builder.appendQueryParameter("ad", "1");
}
// Minimum version is optional.
if (minVersion > 0) {
builder.appendQueryParameter("amv", Integer.toString(minVersion));
}
if (!TextUtils.isEmpty(androidLink)) {
builder.appendQueryParameter("al", androidLink);
}
if (!TextUtils.isEmpty(playStoreAppLink)) {
builder.appendQueryParameter("afl", playStoreAppLink);
}
// Return the completed deep link.
return builder.build().toString();
}
private String generateQueryParameters() throws UnsupportedEncodingException {
StringBuilder queryParameters = new StringBuilder();
//server purposes
queryParameters.append("?*code*");
if (!customParameters.isEmpty()) {
for (Map.Entry<String, String> parameter : customParameters.entrySet()) {
queryParameters.append(String.format("&%1s=%2s", parameter.getKey(), parameter.getValue()));
}
}
return URLEncoder.encode(queryParameters.toString(), "UTF-8");
}
关于android - 如何使用 Firebase 从动态链接获取额外参数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38251166/