iphone - 将非事件 UIView 捕获为 UIImage

Question

下面的代码运行良好，但仅抓取屏幕上可见的 UIView。 如何获取当前未显示的 UIView？

谢谢!

    //Take a screenshot of the view...
UIGraphicsBeginImageContext(View_1.frame.size);
    [View_1.layer renderInContext:UIGraphicsGetCurrentContext()];
UIImage *View_1 = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
UIImageWriteToSavedPhotosAlbum(View_1, nil, nil, nil);

//...and attach it as an image to the email
NSData *myData3 = UIImagePNGRepresentation(View_1);
[picker addAttachmentData:myData3 mimeType:@"image/png" fileName:@"screenshot2"];   

Answer 1

如果您的意思是像 view.hidden = YES; 中那样隐藏，那么您将无法绘制它，您可以将其从 super View 中删除，甚至调用 view.hidden = NO; 在绘制之前，然后 view.hidden = YES; 在绘制之后

示例

//Take a screenshot of the view...
UIGraphicsBeginImageContext(View_1.frame.size);
//Set it to visible
View_1.hidden = NO;
[View_1.layer renderInContext:UIGraphicsGetCurrentContext()];
UIImage *View_1 = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
UIImageWriteToSavedPhotosAlbum(View_1, nil, nil, nil);
//Hide it again
View_1.hidden = YES;
//...and attach it as an image to the email
NSData *myData3 = UIImagePNGRepresentation(View_1);
[picker addAttachmentData:myData3 mimeType:@"image/png" fileName:@"screenshot2"];