iphone - 将 iphone 中当前日期的纪元时间转换为小时前、分钟前

Question

我的纪元时间是1347522689。现在我想显示从当前日期算起多少小时前、几分钟前的时间。我是这个领域的新手，请向我展示一些代码或任何建议，谢谢。

谢谢

Answer 1

NSString *epochTime = @"1347522689";
NSTimeInterval epochInterval = [epochTime longLongValue];
NSDate *epochNSDate = [[NSDate alloc] initWithTimeIntervalSince1970:epochInterval];
NSDateFormatter *dateFormatterEpoch = [[NSDateFormatter alloc] init];
[dateFormatterEpoch setDateFormat:@"yyyy-MM-dd HH:mm:ss zzz"];
NSString *epochDate = [dateFormatterEpoch stringFromDate:epochNSDate];

NSDate *currentDateNSDate = [NSDate date];
NSDateFormatter *dateFormatterCurrent = [[NSDateFormatter alloc] init];
[dateFormatterCurrent setDateFormat:@"yyyy-MM-dd HH:mm:ss zzz"];
NSString *currentDate = [dateFormatterCurrent stringFromDate:currentDateNSDate];


NSLog(@"epochDate = %@",epochDate);
NSLog(@"currentDate = %@", currentDate);

NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];

NSUInteger unitFlags = NSMonthCalendarUnit | NSDayCalendarUnit | NSYearCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit;

NSDateComponents *components = [gregorian components:unitFlags fromDate:epochNSDate toDate:currentDateNSDate options:0];

NSInteger year = [components month];
NSInteger months = [components month];
NSInteger days = [components day];
NSInteger hours = [components hour];
NSInteger min = [components minute];
NSInteger sec = [components second];


NSLog(@"Year Difference = %@\n Month Difference = %@\n, Days Difference = %@\n, Hours Difference = %@\n ,Minutes Difference = %@\n second Difference = %@\n", [[NSNumber numberWithInteger:year] stringValue] ,[[NSNumber numberWithInteger:months] stringValue], [[NSNumber numberWithInteger:days] stringValue], [[NSNumber numberWithInteger:hours] stringValue], [[NSNumber numberWithInteger:min] stringValue],[[NSNumber numberWithInteger:sec] stringValue]);