android - 将 Intent 显式寻址到动态广播接收器

Question

我是 Android 的新手，正在尝试了解应用程序之间的通信。

我正在尝试编写 3 个可以相互通信的小应用程序。如果您想向所有人发送消息，您只需使用隐式广播。

隐式 Intent intent.setAction("com.example.myChatMessage")

如果你只想给 1 个特定的接收器分配地址，我用

显式 Intentintent.setComponent("com.example.test.android.broadcastreceiver.b", "com.example.test.android.broadcastreceiver.b.myBroadcastReceiver")

当广播接收器是一个单独的类并在 AndroidManifest.xml 中定义时，这是可行的。

我的问题:是否可以显式地址动态注册的广播接收器？

package com.example.test.android.broadcastreceiver.b;

public class MainActivity extends Activity {

private final IntentFilter intentfilter = new IntentFilter("com.example.myChatMessage");
private myBroadcastReceiver broadcastreceiver;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    broadcastreceiver = new myBroadcastReceiver();
    registerReceiver(broadcastreceiver, intentfilter);
}

public static class myBroadcastReceiver extends BroadcastReceiver{
    @Override
    public void onReceive(Context context, Intent intent) {
        String message = intent.getStringExtra("message");
        Log.d("message", "B received: "+message);       
    }
}
}

它接收所有隐式广播但没有显式广播 - 我不知道如何处理它。你能帮帮我吗？

Answer 1

似乎不可能向动态注册的广播接收器发送明确的 Intent 。在 AndroidManifest.xml 中注册接收器是唯一的方法。

If you dynamically register a BroadcastReceiver – by calling Context.registerReceiver() – you supply a BroadcastReceiver instance ... If you try to send an Intent to the receiver by naming the class of the BroadcastReceiver, it will never get delivered .. The Android system will not match the Intent you declared to the class of the BroadcastReceiver instance you registered.

来源:http://onemikro2nd.blogspot.com/2013/09/darker-corners-of-android.html