ios - 连接到 iOS 中需要用户名和密码的 JSON API

Question

我有一个 URL，当在浏览器 (EG Safari) 中输入该 URL 请求用户名和密码时，响应 API 以 JSON 的形式返回。

现在我正在尝试在我的 iOS 应用程序中连接到此 API，以便我可以使用 JSON 数据，但我不确定我是否以正确的方式处理它。

NSString *post = [NSString stringWithFormat:@"&Username=%@&Password=%@",@"username",@"password"];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]];

NSString *string = [NSString stringWithFormat:@"jsonURL"];

NSURL *url = [NSURL URLWithString:string];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];

[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"];
[request setHTTPBody:postData];

NSURLConnection *connection = [[NSURLConnection alloc]initWithRequest:request delegate:self];

if(connection)
{
   NSLog(@"connection success");
}
else
{
    NSLog(@"connection could not be made");
}

NSLog 将返回“连接成功”响应。但是，我似乎无法将 JSON 响应加载到 NSDictionary 或 NSArray 中。我在这里使用了 NSJSONSerialization。

NSMutableData *urlData;

- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response {

urlData = [[NSMutableData alloc] init];
NSLog(@"DID RECEIVE RESPONSE %@", urlData);
}


- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData*)data {

[urlData appendData:data];

}

- (void)connectionDidFinishLoading:(NSURLConnection *)connection {

    NSLog(@"FINISHED LOADING DATA %@", connection);

    NSError *jsonParsingError = nil;

    NSDictionary *parsedObject = [NSJSONSerialization JSONObjectWithData:urlData options:0 error:&jsonParsingError];

    if (jsonParsingError) {
    NSLog(@"JSON ERROR: %@", [jsonParsingError localizedDescription]);
}   else {
    NSLog(@"Parsed Object is %@", parsedObject);
  }

}

这是来自 NSLog 的 JSON 错误:“JSON 错误:操作无法完成。(Cocoa 错误 3840。)”

我哪里出错了？提前致谢。

Answer 1

 NSString *jsonstring = [NSString stringWithFormat:@"{\"userName\":\"%@\",\"password\":\"%@\",\"loginFrom\":\"2\",\"loginIp\":\"%@\"}",[username_text removequotes],[password_text removequotes],ipaddress];//The removeQuotes method is used to escape sequence the " to \" so that the json structure won't break. If the user give " in the username or password field and if we dint handle that the json structure will break and may give an expection.
NSLog(@"the json string we are sending is %@",jsonstring);
NSData *strdata = [json1  dataUsingEncoding:NSUTF8StringEncoding];
NSString *fixedURL =[NSString stringWithFormat:@"%@",loginURL];//the url is saved in loginURL variable.
NSURL *url = [NSURL URLWithString:fixedURL];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:url cachePolicy:NSURLRequestReloadIgnoringCacheData timeoutInterval:30];
[request setHTTPMethod:@"POST"];
[request setHTTPBody: strdata];
conn = [[NSURLConnection alloc] initWithRequest:request delegate:self];
if (conn) {
    NSLog(@"Connected to service waiting for response");
}

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