我尝试使用reactjs创建一个幸运抽奖轮,首先,我需要将所有输入数据放置到某个XY位置。下面是我需要的预期输出 XY 位置示例。
var renderData = ["1","2","3","4","5","6","7","8","9","10","11","12"];
React.createElement('div', { className: '_data'},
renderData.map((index,item)=>{
var itemPosition = index / renderData.length * 360;
var itemX = itemPosition * Math.PI/180;
var itemY = itemPosition * Math.PI/180;
return React.createElement('div', { className: '_items',
style:{top:itemX,left:itemY}
},item);
})
)
因此,我使用 createElement
为每个数据创建 div
,然后使用 top
和 left
创建XY 位置。
如何计算每个div
的XY位置
更新
尝试了@keikai的答案后
var renderData = ["1","2","3","4","5","6","7","8","9","10","11","12"];
const r = 350;
const len = renderData.length;
const radiusList = renderData.map(x => (360 / len) * (x - 1));
const positionPairList = radiusList.map(x => ({
x: Math.sin((Math.PI * x) / 180) * r,
y: Math.cos((Math.PI * x) / 180) * r
}));
React.createElement('div', { className: '_data'},
renderData.map((item, index) => {
return React.createElement('div', { className: `_items`,
style:{top:`${positionPairList[index].x.toFixed(2)}px`,left:`${positionPairList[index].y.toFixed(2)}px`}
},item);
})
)
- 所有数据均旋转 0deg
- 子 div 仍未放置在父 div 内的正确位置
- 顺时针方向,从10开始?
最佳答案
更新:使用时钟样式旋转显示
import React from "react";
import ReactDOM from "react-dom";
import "./styles.css";
function App() {
const n = 12;
const r = 500;
const radiusList = Array.from(Array(n).keys()).map(x => (360 / n) * x);
const positionPairList = radiusList.map(item => ({
x: Math.sin((Math.PI * item) / 180) * r,
y: Math.cos((Math.PI * item) / 180) * r
}));
return (
<div className="App">
{positionPairList.map((item, index) => {
const offset = index === 0 ? n : 0;
return (
<div
className="Parts"
style={{
top: `${r - item.y.toFixed(0)}px`,
right: `${r + 200 - item.x.toFixed(0)}px`,
transform: `rotate(${radiusList[index]}deg)`
}}
>
{index + offset}
</div>
);
})}
</div>
);
}
const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);
关于javascript - 计算车轮数据 XY 位置,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59409182/