javascript - JSON 文件仅显示最后一个条目，尽管 id 不同

Question

我的 json 文件如下所示:

var obj = {
 Dilse : {"name":"Dil Se Re","length":"5:40","songType":"Romantic"},
 Dilse : {"name":"Jiya Jale","length":"3:50","songType":"Self Description"},
 Dilse : {"name":"Chaiyya Chaiyya","length":"4:30","songType":"Masti"},

 Rockstar : {"name":"Sadda haq","length":"5:40","songType":"Romantic"},
 Rockstar : {"name":"Tum ho Pas Mere","length":"3:50","songType":"Self Description"},
 Rockstar : {"name":"Sheher me","length":"4:30","songType":"Masti"},
}

我想在单击 Dil se 时检索 Dilse 条目，并在单击 Rockstar 时检索 Rockstar 条目。我的页面上已经有 Dilse 和 Rockstar 条目。

JS 函数如下所示:

function dilSe(){

            document.getElementById("div0").innerHTML = ""; var k =0;
            if(xhr.readyState==4){
            if(xhr.status==200){
                var data=xhr.responseText;
                var arr=eval(data);
                for(var i=0;i<3;i++){             //I dont know if I should itearte like this !?

                            var link=document.createElement('a');
                            link.id='name1'+k++;
                            link.innerHTML="Song Name: " +obj.Dilse.name+"<br/>"+"Song Length: "+obj.Dilse.length+"<br/>"+"Song Type: "+obj.Dilse.songType+"<br/><br/>";
                            console.log("link.id is "+link.id);
                            link.setAttribute('href','#');

                            link.addEventListener('click',albums[link.id]);

                            div0.appendChild(link);
                            } 
                }else{
                    div0.innerHTML="Oops, error in communication!";
                    div0.style.color="red";
                }
            }
}


function rockStar(){

            document.getElementById("div0").innerHTML = ""; var k =0; var r=3;
            if(xhr.readyState==4){
            if(xhr.status==200){
                var data=xhr.responseText;
                var arr=eval(data);
                for(var i=0;i<3;i++){       //I dont know if I should itearte like this !?

                            var link=document.createElement('a');
                            link.id='name2'+k++;
                            link.innerHTML="Song Name: " +obj.Rockstar.name+"<br/>"+"Song Length: "+obj.Rockstar.length+"<br/>"+"Song Type: "+obj.Rockstar.songType+"<br/><br/>";
                            console.log("link.id is "+link.id);
                            link.setAttribute('href','#');
                            console.log("obj.rockstar.name is "+obj.Rockstar.name);
                            link.addEventListener('click',albums[link.id]);

                            div0.appendChild(link);
                            } 
                }else{
                    div0.innerHTML="Oops, error in communication!";
                    div0.style.color="red";
                }
            }
}

但最后我得到的只是 Dilse 的最后一个条目(即 Chaiyya Chaiyya)和 Rockstar 的最后一个条目(即 Sheher me)。我希望显示所有三个条目。

Answer 1

您的 JSON 对象不正确。显然，你不能用同一个键有多个条目(你正在做的是告诉 JS:“詹姆斯是这个人。啊不，詹姆斯是另一个人。啊不，詹姆斯是第三个人”。当然，他记得只有最后一个。

你需要使用数组。最简单的解决方案是将 JSON 修改为如下所示:

var obj = {
 Dilse :
 [
    {"name":"Dil Se Re","length":"5:40","songType":"Romantic"},
    {"name":"Jiya Jale","length":"3:50","songType":"Self Description"},
    {"name":"Chaiyya Chaiyya","length":"4:30","songType":"Masti"},
 ],

 Rockstar :
 [
    {"name":"Sadda haq","length":"5:40","songType":"Romantic"},
    {"name":"Tum ho Pas Mere","length":"3:50","songType":"Self Description"},
    {"name":"Sheher me","length":"4:30","songType":"Masti"},
 ],
}

还有其他可能的选项，例如单个数组(非关联)，其中过去的键作为每个对象内的值之一，但这需要您迭代整个数组才能找到您想要的东西.