过去 2 个小时我一直在研究这段代码。我根本找不到错误。使用下面的代码，表头和正文显示，但标题不可排序。我尝试了脚本代码的各种变体，但无济于事。我错过了什么？
<!DOCTYPE html>
<head>
<script type="text/javascript" src="./jquery-1.11.1.min.js"></script>
<script type="text/javascript" src="./Mottie-tablesorter-c1ce076/js/jquery.tablesorter.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
$("table").tablesorter();
}
);
</script>
</head>
<?php
/* Attempt MySQL server connection. Assuming you are running MySQL
server with default setting (user 'root' with no password) */
$link = mysqli_connect("localhost", "SECRET", "SECRET", "SECRET");
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Attempt select query execution
$sql = "SELECT * FROM persons";
if($result = mysqli_query($link, $sql)){
if(mysqli_num_rows($result) > 0){
echo "<table class=\"tablesorter\">";
echo "<thead>";
echo "<tr>";
echo "<th>First Name</th>";
echo "<th>Last Name</th>";
echo "<th>Email</th>";
echo "<th>FFID</th>";
echo "<th>Street</th>";
echo "<th>City</th>";
echo "<th>State</th>";
echo "<th>Zip</th>";
echo "<th>Home Fire Dept</th>";
echo "<th>Shirt Size</th>";
echo "<th>Additional Shirts</th>";
echo "<th>Friday Class</th>";
echo "<th>Saturday Class</th>";
echo "<th>Sunday Class</th>";
echo "</tr>";
echo "</thead>";
while($row = mysqli_fetch_array($result)){
echo "<tbody><tr>";
echo "<td>" . $row['first_name'] . "</td>";
echo "<td>" . $row['last_name'] . "</td>";
echo "<td>" . $row['email_address'] . "</td>";
echo "<td>" . $row['ffid_num'] . "</td>";
echo "<td>" . $row['address_street'] . "</td>";
echo "<td>" . $row['address_city'] . "</td>";
echo "<td>" . $row['address_state'] . "</td>";
echo "<td>" . $row['address_zip'] . "</td>";
echo "<td>" . $row['fire_dept'] . "</td>";
echo "<td>" . $row['wants_tshirt'] . "</td>";
echo "<td>" . $row['shirt_size'] . "</td>";
echo "<td>" . $row['additional_shirts'] . "</td>";
echo "<td>" . $row['friday_class'] . "</td>";
echo "<td>" . $row['saturday_class'] . "</td>";
echo "<td>" . $row['sunday_class'] . "</td>";
echo "</tr></tbody>";
}
echo "</table>";
// Close result set
mysqli_free_result($result);
} else{
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// Close connection
mysqli_close($link);
?>
</html>
最佳答案
只需在 while 循环之外添加 和 即可。
echo "</thead><tbody>";
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['first_name'] . "</td>";
echo "<td>" . $row['last_name'] . "</td>";
echo "<td>" . $row['email_address'] . "</td>";
echo "<td>" . $row['ffid_num'] . "</td>";
echo "<td>" . $row['address_street'] . "</td>";
echo "<td>" . $row['address_city'] . "</td>";
echo "<td>" . $row['address_state'] . "</td>";
echo "<td>" . $row['address_zip'] . "</td>";
echo "<td>" . $row['fire_dept'] . "</td>";
echo "<td>" . $row['wants_tshirt'] . "</td>";
echo "<td>" . $row['shirt_size'] . "</td>";
echo "<td>" . $row['additional_shirts'] . "</td>";
echo "<td>" . $row['friday_class'] . "</td>";
echo "<td>" . $row['saturday_class'] . "</td>";
echo "<td>" . $row['sunday_class'] . "</td>";
echo "</tr>";
}
echo "</tbody></table>";
关于javascript - Tablesorter 将不会显示可排序的标题，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/25278155/