我有一个电子表格,我正在将其转换为 json。我可以使用 php 代码进行转换。但我想命名该数组。我该怎么做..请帮助..Php 和输出以及所需的输出是提到过。
Required output
["Name"{"Timestamp":"7\/24\/2015 12:42:41","Name":"ADADSADS","Type":"ASDSD","Place":"ASDSADD","Date":"ASDSD","Time":"ASDSD","Free":"ASDSD","Organizer":"ASDSD","Contact":"ASDSD","Description":"ASDSD","id":0}]
Output from the below code
[{"Timestamp":"7\/24\/2015 12:42:41","Name":"ADADSADS","Type":"ASDSD","Place":"ASDSADD","Date":"ASDSD","Time":"ASDSD","Free":"ASDSD","Organizer":"ASDSD","Contact":"ASDSD","Description":"ASDSD","id":0}]
<?php
/*
* Converts CSV to JSON
* Example uses Google Spreadsheet CSV feed
* csvToArray function I think I found on php.net
*/
header('Content-type: application/json');
// Set your CSV feed
$feed = 'google doc url';
// Arrays we'll use later
$keys = array();
$newArray = array();
// Function to convert CSV into associative array
function csvToArray($file, $delimiter) {
if (($handle = fopen($file, 'r')) !== FALSE) {
$i = 0;
while (($lineArray = fgetcsv($handle, 4000, $delimiter, '"')) !== FALSE) {
for ($j = 0; $j < count($lineArray); $j++) {
$arr[$i][$j] = $lineArray[$j];
}
$i++;
}
fclose($handle);
}
return $arr;
}
// Do it
$data = csvToArray($feed, ',');
// Set number of elements (minus 1 because we shift off the first row)
$count = count($data) - 1;
//Use first row for names
$labels = array_shift($data);
foreach ($labels as $label) {
$keys[] = $label;
}
// Add Ids, just in case we want them later
$keys[] = 'id';
for ($i = 0; $i < $count; $i++) {
$data[$i][] = $i;
}
// Bring it all together
for ($j = 0; $j < $count; $j++) {
$d = array_combine($keys, $data[$j]);
$newArray[$j] = $d;
}
// Print it out as JSON
echo json_encode($newArray);
?>
最佳答案
这不是有效的 json。这样做有什么意义?
substr_replace() replaces a copy of string delimited by the start and (optionally) length parameters with the string given in replacement.
mixed substr_replace ( mixed $string , mixed $replacement , mixed $start [, mixed $length ] )
echo substr_replace(json_encode($newArray), '"Name"', 1, 0);
但如果你的意思是 { "Name": <JSON> }
那么你可以这样做:
echo json_encode(array("Name" => $newArray));
关于javascript - 使用php转换为json,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31624486/