javascript 函数链中的变量赋值

Question

试图让这个变得简单一点:

    //first named function
    function tryMe(x){
        tryMeAgain(x);
    };

    //second named function
    function tryMeAgain(y){
        return y;
    };

    //assign the result of first function (which will actually be the result of the second function) to a var
    var testTry = tryMe('worth a shot');

    console.log(testTry); //undefined! But I would like 'testTry' to return 'worth a shot'

所以我有两个问题:

1. 这是为什么？
2. 如何正确分配“testTry”？

EDIT BELOW: So the responses all make sense and I think my problem may lay somewhere else in my code. My attempt to simplify the question may have overlooked another piece of the puzzle. I'm including a new version and hoping you all can shed some light:

  var runtime = (function(){

        var $jq = jQuery.noConflict(true);

        function Runtime(){
            this.$jq = $jq;
        }

        Runtime.prototype.method1 = function( _value, _callback ){
            setTimeout(function(){ console.log('dependency1_resolved');
                _callback.apply(this, [{valIs:_value}]);
            }.bind(this), (Math.random() * 1000));
        };

        Runtime.prototype.method2 = function( _value, _callback ){
            var self = this;
            setTimeout(function(){ console.log('dependency2_resolved');
                _callback.apply(self, [{differntValIs:3}]);
            }.bind(this), (Math.random() * 1000));
        };

        Runtime.prototype.method3 = function( _value, _callback ){
            setTimeout(function(){ console.log('dependency3_resolved');
                _callback.apply(this, [{valIs:_value['differntValIs'] *= 4}]);
            }.bind(this), (Math.random() * 1000));
        };

        return new Runtime();
    })();


  runtime.initialize(function( $ ){
    function firstCalc(firstInput){
        return runtime.method1(firstInput,secondCalc);
    };
    function secondCalc(secondInput){
        return runtime.method2(secondInput, thirdCalc);
    };
    function thirdCalc(thirdInput){
        return runtime.method3(thirdInput, fourthCalc);
    };
    function fourthCalc(ourResult){
        //console.log( ourResult );
        return ourResult;
    };

    var _value = firstCalc(4); //this is undefined!!
});

Answer 1

您从 tryMeAgain 返回值，而不是从 tryMe 方法返回值，因此返回的默认值是 undefined

//first named function
function tryMe(x) {
  return tryMeAgain(x);//need to return the value returned by tryMeAgain to the caller of tryMe
};

//second named function
function tryMeAgain(y) {
  return y;
};

//assign the result of first function to a var
var testTry = tryMe('worth a shot');

snippet.log(testTry);

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