javascript - Angular - 返回不工作对象的差异

Question

如何返回两个对象的差异？

$scope.a = [
   {name: "Lunchmeat"},
   {name: "Apple"},
   {name: "Bread"},
   {name: "Milk"},
   {name: "Mustard"},
   {name: "Cheese"}
];
$scope.b = [
   {name: "Bread"},
   {name: "Milk"},
   {name: "Mustard"},
   {name: "Cheese"}
]; 

$.grep($scope.a, function (el) {
        if ($.inArray($scope.b,el) == -1) console.log(el);//not working
  });

我正在寻找的输出是Object [{name: "Lunchmeat"},{name: "Apple"}]，因为这就是区别。

有人可以帮忙吗？

Answer 1

我正在使用underscore.js库及其功能区别:

"difference_.difference(array, *others) Similar to without, but returns the values from array that are not present in the other arrays.

_.difference([1, 2, 3, 4, 5], [5, 2, 10]); => [1, 3, 4]"

在你的情况下，它是:

$scope.someVar =_.difference($scope.a,$scope.b);