javascript - 如何简化/精简这段代码？ (对象检查到函数调用中)

Question

首先，这是我的 urlObject 的样子:

{
    term_id_1: "2155"
    term_id_2: "2894"
    ticker_1: "SPY"
    ticker_2: "SPY"
}

我最多可以有 3 个术语和代码，例如:

ticker_1、ticker_2、ticker_3

及其匹配的标签:

term_id_1、term_id_2、term_id_3

这是我当前的函数，用于检查股票代码和标签组合是否存在，然后调用另一个函数:

function rebuildContainer(urlObject) {
    console.log('urlObject',urlObject);

    if (urlObject.ticker_1 && urlObject.term_id_1) {
        var tickerObj = {};
            tickerObj.ticker = urlObject.ticker_1;
        var tagObj = {};
            tagObj.term_id = urlObject.term_id_1;
        saveTickerTags(tickerObj, tagObj);
    }

    if (urlObject.ticker_2 && urlObject.term_id_2) {
        var tickerObj = {};
            tickerObj.ticker = urlObject.ticker_2;
        var tagObj = {};
            tagObj.term_id = urlObject.term_id_2;
        saveTickerTags(tickerObj, tagObj);
    }

    if (urlObject.ticker_3 && urlObject.term_id_3) {
        var tickerObj = {};
            tickerObj.ticker = urlObject.ticker_3;
        var tagObj = {};
            tagObj.term_id = urlObject.term_id_3;
        saveTickerTags(tickerObj, tagObj);
    }
}

这感觉很容易简化，你会怎么做？

Answer 1

还没有真正测试过太多，但这应该可以工作，这样你就不必对 id 进行硬编码......

function rebuildContainer(urlObject) {
    // get the keys that contain the 'ticker' text
    Object.keys(urlObject).filter(function (k) {
        return k.indexOf('ticker') > -1;
    }).forEach(function (k) {
        // get the number at the end and look it up on the urlObject
        var termId = urlObject['term_id_' + k.match(/\d+$/)[0]];
        // if it is defined, save the object
        if(termId !== undefined) {
            var tickerObj = {};
            var tagObj = {};
            tickerObj.ticker = urlObject[k];
            tagObj.term_id = termId;
            saveTickerTags(tickerObj, tagObj);
        }
    });
}