我不想在 pageAge 或 pageMore 上执行 if 语句。当我转到 pageAge 时,它可以工作,它不会执行脚本,但当我转到 pageMore 时,它会执行脚本。我不确定在这种情况下使用哪个运算符。当我将 pageMore 放在 ||
之前时,它可以在该页面上运行,但不能在其他页面上运行。
if ( top.location.pathname != pageAge || pageMore) {
//if not verified go to connect
$("body").css("display", "none");
if (age === null && top.location.pathname != pageConnect) {
window.location.href = pageConnect;
}
//if to young go to age page while cookie is found (1day)
if (age == toYoung) {
window.location.href = pageAge;
}
//if already verified go to like page.
if (age == legal && top.location.pathname === pageConnect) {
window.location.href = pageLike;
}
}
最佳答案
应该是:
if ( top.location.pathname != pageAge && top.location.pathname != pageMore)
关于当页面等于 X 时,javascript 逻辑运算符不执行功能,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33935672/