javascript - ajax未捕获引用错误: field_inputs is not defined

Question

这是自定义表单，我不知道为什么我一直有“Uncaught ReferenceError:field_inputs is not Defined”错误

如果您还有缩短代码的方法，我很想知道如何实现

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
								<script>
								
									$(document).ready(function () {
										$( ".form" ).change(function() {
											$( ".addfromform" ).empty();
											field_include();
										});
									});
									
									function field_include()
									{
										var form_id = $( ".form" ).val();
										
										$.ajax({
										url: 'ajax/field_include.php',
										type: 'POST',
										data: {
											form_id : form_id
										},
										success: function(data) 
										{
												var	fields = data;
												var field = fields.split(";").filter(Boolean);
												$.each(field, function(i, val){
													var field_val = val.split(",");
													$( ".addfromform" ).append('<div class="form-group"><label class="col-lg-2 control-label mt10">'+field_val[2]+'</label><div class="col-xs-10"><label for="'+field_val[1]+'" class="field prepend-icon"><input type="'+field_val[0]+'" name="'+field_val[1]+'" id="'+field_val[1]+'" class="gui-input" placeholder="'+field_val[3]+'" autocomplete="off"><label for="'+field_val[1]+'" class="field-icon"><i class="fa fa-user"></i></label></label></div></div>').fadeIn('slow');
												
												
													if (input_ids != null)
													{
														var input_ids = ""+input_ids+","+field_val[1]+"";
														$(".date").data("input_name", ""+input_ids+"");
													}
													else
													{
														var input_ids = ""+field_val[1]+"";
														$(".date").data("input_name", ""+input_ids+"");
													}
												});
											}
										});
									}
									
									function save_guest()
									{
										var field_names = $(".date").data("input_name");
										
										var field_name = field_names.split(",").filter(Boolean);
										$.each(field_name, function(i, input_val){
											
											if(typeof(field_inputs) != "undefined" && field_inputs !== null)
											{
												var input_date = $( "."+input_val+"" ).val();
												var field_inputs = ""+field_inputs+""+input_val+","+input_date+";";
											}
											else
											{
												var input_date = $( "."+input_val+"" ).val();
												var field_inputs = ""+input_val+","+input_date+";";
											}
										});
										
										$.ajax({
											url: 'ajax/save_new_guest.php',
											type: 'POST',
											data: {
												field : field_inputs
											},
											success: function(data) 
											{
												document.location.href="../../guest.php";
											}
										});
									}

								</script>

<button onclick="save_guest();" class="button btn-primary"> Add guest </button>

我是新主题 AJAX jquery

Answer 1

您必须将 field_inputs 放在 each 函数之外，以便您的 ajax 可以访问变量

function save_guest()
    {
    var field_inputs = null;
    var field_names = $(".date").data("input_name");
    var field_name = field_names.split(",").filter(Boolean);
    $.each(field_name, function(i, input_val){
        if(typeof(field_inputs) != "undefined" && field_inputs !== null)
        {
            var input_date = $( "."+input_val+"" ).val();
            field_inputs = ""+field_inputs+""+input_val+","+input_date+";";
        }
        else
        {
            var input_date = $( "."+input_val+"" ).val();
            field_inputs = ""+input_val+","+input_date+";";
        }
    });

    $.ajax({
        url: 'ajax/save_new_guest.php',
        type: 'POST',
        data: {
            field : field_inputs
        },
        success: function(data) 
        {
            document.location.href="../../guest.php";
        }
    });
}