javascript - 雅虎财经 xchange - 获取最后更新时间

标签 javascript time yahoo yql

我正在Yahoo Finance xchange上查询,但似乎更新时间不是最新的。看起来是随机的,对于每次刷新,这个值都会变化,有时更新最多,有时更新较少。

有办法始终获取上次更新时间吗?

谢谢。

        $.getJSON("https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20yahoo.finance.xchange%20where%20pair%20in%20(%22USDUSD%22%2C%22USDEUR%22%2C%20%22USDJPY%22%2C%20%22USDCNY%22%2C%20%22USDGBP%22%2C%20%22USDBRL%22%2C%20%22EUREUR%22%20%2C%22EURUSD%22%2C%20%22EURJPY%22%2C%20%22EURCNY%22%2C%20%22EURGBP%22%2C%20%22EURBRL%22)&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys&callback=", function (data) {
        var indices =   '<p style=\"border:1px solid #ccc; width:auto; padding:0 10px; background:#ddd;\"><strong>' + data.query.results.rate[0].Name + '</strong> ' + money(data.query.results.rate[0].Rate) + '</p>' +
                        '<p><strong>' + data.query.results.rate[1].Name + '</strong> (Fechamento ' + money(data.query.results.rate[1].Rate) + ') - ' + data.query.results.rate[1].Date + ' - ' + data.query.results.rate[1].Time + '</p>' +
                        '<p><strong>' + data.query.results.rate[2].Name + '</strong> (Fechamento ' + money(data.query.results.rate[2].Rate) + ') - ' + data.query.results.rate[2].Date + ' - ' + data.query.results.rate[2].Time + '</p>' +
                        '<p><strong>' + data.query.results.rate[3].Name + '</strong> (Fechamento ' + money(data.query.results.rate[3].Rate) + ') - ' + data.query.results.rate[3].Date + ' - ' + data.query.results.rate[3].Time + '</p>' +
                        '<p><strong>' + data.query.results.rate[4].Name + '</strong> (Fechamento ' + money(data.query.results.rate[4].Rate) + ') - ' + data.query.results.rate[4].Date + ' - ' + data.query.results.rate[4].Time + '</p>' +
                        '<p><strong>' + data.query.results.rate[5].Name + '</strong> (Fechamento ' + money(data.query.results.rate[5].Rate) + ') - ' + data.query.results.rate[5].Date + ' - ' + data.query.results.rate[5].Time + '</p>' +
                        '<p style=\"border:1px solid #ccc; width:auto; margin:20px 0 0; padding:0 10px; background:#ddd;\"><strong>' + data.query.results.rate[6].Name + '</strong> ' + money(data.query.results.rate[6].Rate) + '</p>' +
                        '<p><strong>' + data.query.results.rate[8].Name + '</strong> (Fechamento ' + money(data.query.results.rate[8].Rate) + ') - ' + data.query.results.rate[8].Date + ' - ' + data.query.results.rate[8].Time + '</p>' +
                        '<p><strong>' + data.query.results.rate[7].Name + '</strong> (Fechamento ' + money(data.query.results.rate[7].Rate) + ') - ' + data.query.results.rate[7].Date + ' - ' + data.query.results.rate[7].Time + '</p>' +
                        '<p><strong>' + data.query.results.rate[9].Name + '</strong> (Fechamento ' + money(data.query.results.rate[9].Rate) + ') - ' + data.query.results.rate[9].Date + ' - ' + data.query.results.rate[9].Time + '</p>' +
                        '<p><strong>' + data.query.results.rate[10].Name + '</strong> (Fechamento ' + money(data.query.results.rate[10].Rate) + ') - ' + data.query.results.rate[10].Date + ' - ' + data.query.results.rate[10].Time + '</p>' +
                        '<p><strong>' + data.query.results.rate[11].Name + '</strong> (Fechamento ' + money(data.query.results.rate[11].Rate) + ') - ' + data.query.results.rate[11].Date + ' - ' + data.query.results.rate[11].Time + '</p>';
        $('#info').html(indices);
    });
    money = function (n) {
        var
            c = 4,
            d = ',',
            t = '.',
            s = n < 0 ? "-" : "",
            i = parseInt(n = Math.abs(+n || 0).toFixed(c)) + "",
            j = (j = i.length) > 3 ? j % 3 : 0;
        return s + (j ? i.substr(0, j) + t : "") + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + t) + (c ? d + Math.abs(n - i).toFixed(c).slice(2) : "");
    };

最佳答案

好吧,我最终为数组(映射)中的每个元素构建了一个日期,然后将它们过滤到最旧的日期(减少)

你想用这个日期做什么,我不确定,但这里是......

已更新

更新为返回包含最新日期/时间戳的完整 JSON 记录(而不是仅返回最新日期)

// sample response
var response = {"query":{"count":12,"created":"2016-04-29T20:13:39Z","lang":"en-us","results":{"rate":[{"id":"USDUSD","Name":"USD/USD","Rate":"1.0000","Date":"N/A","Time":"N/A","Ask":"1.0000","Bid":"1.0000"},   
{"id":"USDEUR","Name":"USD/EUR","Rate":"0.8775","Date":"4/29/2016",  "Time":"12:38pm","Ask":"0.8777","Bid":"0.8775"},{"id":"USDJPY","Name":"USD/JPY","Rate":"107.3910","Date":"4/29/2016","Time": "2:55pm","Ask":"107.3940","Bid":"107.3910"},{"id":"USDCNY","Name":"USD/CNY","Rate":"6.4868","Date":"4/29/2016","Time":"12:49pm","Ask":"6.4878","Bid":"6.4868"},{"id":"USDGBP","Name":"USD/GBP","Rate":"0.6843","Date":"4/29/2016","Time":"1:15pm","Ask":"0.6844","Bid":"0.6843"},{"id":"USDBRL","Name":"USD/BRL","Rate":"3.4492","Date":"4/29/2016","Time":"3:33pm","Ask":"3.4496","Bid":"3.4492"},{"id":"EUREUR","Name":"EUR/EUR","Rate":"1.0000","Date":"1/29/2016","Time":"8:26am","Ask":"1.0002","Bid":"0.9998"},{"id":"EURUSD","Name":"EUR/USD","Rate":"1.1443","Date":"4/29/2016","Time":"3:08pm","Ask":"1.1443","Bid":"1.1443"},{"id":"EURJPY","Name":"EUR/JPY","Rate":"122.5650","Date":"4/29/2016","Time":"4:00pm","Ask":"122.6200","Bid":"122.5100"},{"id":"EURCNY","Name":"EUR/CNY","Rate":"7.4054","Date":"4/29/2016","Time":"2:08pm","Ask":"7.4070","Bid":"7.4037"},{"id":"EURGBP","Name":"EUR/GBP","Rate":"0.7836","Date":"4/29/2016","Time":"3:22pm","Ask":"0.7837","Bid":"0.7836"},{"id":"EURBRL","Name":"EUR/BRL","Rate":"3.9637","Date":"4/29/2016","Time":"4:28pm","Ask":"3.9679","Bid":"3.9595"}]}}};

//console.log(response.query.results.rate);

var times = response.query.results.rate.map(function(elem){

  if( elem.Time === 'N/A' || elem.Time === 0){
    elem.fullDateTimeStamp = elem.Time;
    //console.log(elem);
    return elem;
  }

  // create full date from the time (using time and date combined)
  // 1) is it AM or PM
  var elemIsPm = (elem.Time.substring(elem.Time.length-2).indexOf("am") == -1);  
  
  // 2) remove AM/PM and get hour:min into array
  var elemArr = elem.Time.substring(0, elem.Time.length-2).split(":");
  
  // 3) add 12 hours if PM and not noon
  if( elemIsPm && elemArr[0] != 12){
    elemArr[0] = parseInt(elemArr[0]) + 12;
  }
  //console.log(elemArr[0]);
  
  // 4) however, if it is 12, we deduct 12 if it's not PM
  if( elemArr[0] == 12 && !elemIsPm ){
    elemArr[0] = elemArr[0] - 12;
  }
    
  // 5) create date object
  var elemDateString = elem.Date;
  var elemDateOnly = new Date(elemDateString);
  //console.log(elemDateOnly);
  
  var elemTS = new Date(elemDateOnly.getFullYear(), elemDateOnly.getMonth(), elemDateOnly.getDate(), elemArr[0], elemArr[1], 0, 0);
  elem.fullDateTimeStamp = elemTS;
  
//  console.log(elem);
  
  // 4) return
  return elem;
});

 console.log( times );


var lastOne = times.reduce(function(prevVal, elem) {  
//  console.log('p');
//  console.log(prevVal );
  
//  console.log('e');
//  console.log(elem );
  
  if( prevVal === 'N/A' || prevVal === 0 || prevVal.Time){
    return elem;
  }
  
  //console.log(prevVal.fullDateTimeStamp);
      
  return (prevVal.fullDateTimeStamp < elem.fullDateTimeStamp)? elem : prevVal;
  
}, 0);

document.getElementById('latest').innerHTML = JSON.stringify(lastOne);

console.log('====> ');

console.log( JSON.stringify(lastOne.fullDateTimeStamp) );
Last date:
<div id='latest'></div>

关于javascript - 雅虎财经 xchange - 获取最后更新时间,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36946595/

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