javascript - (PHP) 如何为未选中的复选框设置默认值

Question

我是 PHP 新手。

现在我面临这个关于复选框值的问题。我从这些页面中搜索答案，他们的解决方案不适用于我的情况。

Trying to set default checkbox value if not checked

Post the checkboxes that are unchecked (我不知道该把JS放在哪里)

how do I get all checkbox variables even if not checked from HTML to PHP?

到目前为止，这些是我的代码...

<form method="POST" action="testinsertskill.php">

<br><br>Required Skills : 

**//skip the sql parts because there is no problem from calling the data from database**

<?php
while ($row2 = mysql_fetch_array($result2, MYSQL_ASSOC)) {

?>
<input type="hidden" id="hidden_skills" name="skills[]" value="0" />
<br /><input type="checkbox" id="skills" name="skills[]" value="1" /><?php echo $row2['Skill_Name']; ?><br />

<?php
$count++;
}
?>
<input type="hidden" name="counter" value="<?=$count?>" />

<input type="submit" name="submit" value="Confirm">

</form>

这是 testinsertskill.php 页面

<?php session_start();

        $servername = "localhost";
        $username = "root";
        $password = "rootroot";
        $dbname = "onlinerecruitment";

        // Create connection
        $conn = new mysqli($servername, $username, $password, $dbname);
        // Check connection
        if ($conn->connect_error) {
            die("Connection failed: " . $conn->connect_error);
        } 


$skill = $_POST['skills'];
$count = $_POST['counter'];


for($i = 0; $i < $count; $i++){

    $sql = "INSERT INTO applicant_skill VALUES('".$skill[$i]."')"; 

        $resultt = "";

        if ($conn->query($sql) == TRUE) {
           $resultt = "FINISH";
        } else {
           $resultt = "ERROR";
        }

}

$conn->close();

?>

假设有5个技能可供选择，我选择第2和第4。

数据库中的预期结果应该是 (0,1,0,1,0)，但由于隐藏输入，结果却是 (0,0,1,0,0)。现在我不知道该怎么办，因为我提到的那些链接无法解决我的问题，或者我不知道我必须把它放在哪里。请帮忙。

Answer 1

我假设您还有一些 Skill_Id 那么代码可能如下所示

<form method="POST" action="testinsertskill.php">

<br><br>Required Skills : 

**//skip the sql parts because there is no problem from calling the data from database**

<?php
while ($row2 = mysql_fetch_array($result2, MYSQL_ASSOC)) {

?>
<input type="hidden" name="skills[<?= $row2['Skill_Id'] ?>]" value="0" />
<br /><input type="checkbox" name="skills[<?= $row2['Skill_Id'] ?>]" value="1" /><?= $row2['Skill_Name'] ?><br />

<?php
}
?>

<input type="submit" name="submit" value="Confirm">

</form>

然后插入代码:

//....
foreach($_POST['skills'] as $skillId => $skill){

    $sql = "INSERT INTO applicant_skill VALUES('".$skill."')"; 

        $resultt = "";

        if ($conn->query($sql) == TRUE) {
           $resultt = "FINISH";
        } else {
           $resultt = "ERROR";
        }

}