javascript - 如何获取像这样的字符串删除Java中的重复字符串

Question

我将数组从 jquery 发送到 Controller ，并且该数组在 Controller 中作为字符串获取 String getIdVal = ParamUtil.getString(resourceRequest, "getId");
String getIds 中的值类似于 getIdVal ="1_ABC,2_ABC,3_ABC,4_NMO,5_NMO,6_XYZ";

我正在尝试获得结果，但没有成功。
(考虑到 1 是键 ABC 是值)。
我想从所有键中删除 ABC(即重复值)并在末尾仅附加一次。同时我希望重复值的键应该像这样 (1-2-3_ABC)。
最后字符串应该像这样 "1-2- 3_ABC，4-5_NMO，6_XYZ”

这里我尝试根据逗号进行分割，但我不知道如何解决。

 List<String> keysVals = new ArrayList<String>(Arrays.asList(getIdVal .split(",")));
                String getKeyVal;
                String[] getKeys;
                String key;
                String value;
    for (String getKeysVals : keysVals) {
        getKeyVal = getKeysVals;
        getKeys = getKeyVal.split("\\_");
        key = getKeys[0];
        value = getKeyVal.substring(getKeyVal.lastIndexOf("_") + 1) .trim();
        // i am not getting how to check for dublicate
        }

Answer 1

你的意思是这样的吗？

private static String mergeKeys(String input) {
    Map<String, StringBuilder> valKeys = new TreeMap<>();
    if (! input.isEmpty())
        for (String keyVal : input.split(",")) {
            int idx = keyVal.indexOf('_');
            String key = keyVal.substring(0, idx);
            String val = keyVal.substring(idx + 1);
            StringBuilder builder = valKeys.get(val);
            if (builder == null)
                valKeys.put(val, new StringBuilder(key));
            else
                builder.append('-').append(key);
        }
    StringJoiner result = new StringJoiner(",");
    for (Entry<String, StringBuilder> entry : valKeys.entrySet())
        result.add(entry.getValue().append('_').append(entry.getKey()).toString());
    return result.toString();
}

或者相同逻辑的缓慢版本，使用string = string + string(哎呀!):

private static String mergeKeys(String input) {
    Map<String, String> valKeys = new LinkedHashMap<>();
    if (! input.isEmpty())
        for (String keyVal : input.split(",")) {
            int idx = keyVal.indexOf('_');
            String key = keyVal.substring(0, idx);
            String val = keyVal.substring(idx + 1);
            String prevKeys = valKeys.get(val);
            valKeys.put(val, prevKeys == null ? key : prevKeys + "-" + key);
        }
    String result = "";
    for (Entry<String, String> entry : valKeys.entrySet())
        result += "," + entry.getValue() + "_" + entry.getKey();
    return result.substring(1); // skip leading comma
}

测试

System.out.println(mergeKeys("1_ABC,2_ABC,3_ABC,4_NMO,5_NMO,6_XYZ"));

输出

1-2-3_ABC,4-5_NMO,6_XYZ