这是我的代码
$(document).ready(function(){
$("form#one").validate({ // initialize form validation on form 1
// rules & other options
messages: {
input1: "salam"
},
errorPlacement: function(error, element) {
element.focus(function () {
$("#msg_required").html(error);
}).blur(function () {
$("#msg_required").html('');
});
}
});
$("form#two").validate({ // initialize form validation on form 2
// rules & other options,
messages: {
input2: "bah"
},
errorPlacement: function(error, element) {
element.focus(function () {
$("#msg_required").html(error);
}).blur(function () {
$("#msg_required").html('');
}); // default error placement
},
submitHandler: function(form) {
if ($("form#one").valid()) { // test to see if form 1 is valid
$( "form#two" ).submit();
}
return false;
}
});
});
<!-- FORM #1: -->
<br/>
<form action="#" id="one">
<input type="text" name="input1" class="required" />
</form>
<!-- FORM #2: -->
<br/>
<form action="#" id="two">
<input type="text" name="input2" class="required" />
<br />
<span dir="rtl" id="msg_required" class="msg_required"></span>
<br /><br />
<input type="submit" />
</form>
当我提交表单二时,不会显示表单一的错误消息。
(包括 jQuery_Validation_Plugin_1.9.0.js 和 jquery-1.9.1.js
)
最佳答案
无法显示 Form 1 错误,因为单击提交按钮时未提交该错误。您应该像这样运行代码:
$("#submit_btn").on('click' function (){
//run your from submission here
})
<br/>
<form action="#" id="one">
<input type="text" name="input1" class="required" />
</form>
<!-- FORM #2: -->
<br/>
<form action="#" id="two">
<input type="text" name="input2" class="required" />
<br />
<span dir="rtl" id="msg_required" class="msg_required"></span>
<br /><br />
</form>
<!--place the submit button here-->
<button id="submit_btn">submit</button>
现在创建一个函数,单击按钮即可提交 2 个表单
关于javascript - 在JSP页面中使用jquery通过一个提交按钮验证两个表单,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37671075/