您好，我尝试使 jquery 对话框弹出窗口(模态)可以更改为弹出窗口中的其他页面(在现有弹出窗口中加载其他页面)
但我不知道如何通过在 test2.php 中编码来加载模式内的 test3.php
这是我的尝试
test1.php
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<title>jQuery UI Dialog - Default functionality</title>
<link rel="stylesheet" href="//code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css">
<link rel="stylesheet" href="/resources/demos/style.css">
<script src="https://code.jquery.com/jquery-1.12.4.js"></script>
<script src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script>
</head>
<body>
<button id="btn">Click to Popup</button>
<div id="dialog" title="Basic dialog">
here
</div>
<script>
$(function () {
$("#dialog").dialog({
open: function(event, ui) {
$('#dialog').load('test2.php', function() {
alert('Load was performed.');
});
},
modal: true,
autoOpen: false,
title: "jQuery Dialog",
width: 600,
height: 350
});
$("#btn").click(function(){
$('#dialog').dialog('open');
});
});
</script>
</body>
</html>
test2.php
this is test2.php page <br/>
<a href="test3.php"> Go to Page test3.php </a>
test3.php
<p> this is test3.php page </p>
最佳答案
在 test1.php 中尝试一下
$(function () {
$("#dialog").dialog({
open: function(event, ui) {
$('#dialog').load('test2.php', function() {
$('#mylink').click(function(){
$('#dialog').load('test3.php', function() {
alert('Load was performed.');
});
});
});
},
modal: true,
autoOpen: false,
title: "jQuery Dialog",
width: 600,
height: 350
});
$("#btn").click(function(){
$('#dialog').dialog('open');
});
});
test2.php
this is test2.php page <br/>
<button id="mylink">Go to Page test3.php</button>关于javascript - jquery的对话框模式可以改变模式内的页面吗？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/41276136/