javascript - 仅对 AJAX 数据中的非空变量传递参数

Question

这里我想做哪些变量不为空，我想在数据中传递该变量，在这种情况下区域是空的，所以我想传递城市和列表类型的参数，但我不知道该怎么办？

var city = "Karnadaka";
var area = "";
var listing type = "RENT";

$.ajax({
    type: 'GET',
    url: "http://www.domain.com/api/get/searchProperties",
    data: {
        area: area,
        city: city,
        listingType: listing_type
    },
    success: function(data) {
        console.log(data);
    }
});

Answer 1

您可以使用delete删除对象中的属性对

var city = "Karnadaka";
var area = "";
var listing_type = "RENT";

var data={
        area: area,
        city: city,
        listingType: listing_type
    }

for (k in data){
    if(data[k]=="") delete data[k];
}

$.ajax({
    type: 'GET',
    url: "http://www.domain.com/api/get/searchProperties",
    data: data,
    success: function(data) {
        console.log(data);
    }
});