我面临解决问题的问题，需要编写重复代码，但我不希望这样。
所以我想如何解决这个问题作为美丽的编程方面。
我想到了一些解决方案。
1.父对象添加事件绑定(bind)到路由器
例如，用户访问 example.com/#aaa 、 example.com/#bbb 时
我加载路由器主题标签而不是处理该事件。
如果用户访问#aaa，则加载模板aaa。
但我找到了很多引用资料，但我不知道如何实现该解决方案，即在backbone.js上进行父子对象通信
<强>2。父对象添加功能
我认为解决方案是访问 url 存储在路由器中的目标
例如，如果我访问 example.com/#aaa 那么 router 会被写入 target = aaa
然后父对象加载函数并渲染异步ajax加载模板并抛出结果子对象。
但同样我也没有能力实现这一点。
谁来给我指点一下？
许多backbone.js引用资料很差而且很困难。
router.js(我的来源)
var app = app || {};
(function() {
'use strict';
var views = app.view = app.view || {};
app.Router = Backbone.Router.extend({
initialize: function(){
this.bind("all", this.change)
console.log(this.change);
},
routes: {
'situation': 'situationRoute',
'video': 'videoRoute',
'culture': 'cultureRoute',
//와일드카드 디폴트 라우터는 맨 마지막에 삽입.
'*home': 'homeRoute'
},
_bindRoutes: function() {
if (!this.routes) return;
this.routes = _.result(this, 'routes');
var route, routes = _.keys(this.routes);
while ((route = routes.pop()) != null) {
this.route(route, this.routes[route]);
}
},
initialize: function() {
// create the layout once here
this.layout = new views.Application({
el: 'body',
});
},
homeRoute: function() {
var view = new views.Home();
var target = 'Home';
this.layout.renderSubpage(target);
this.layout.setContent(view);
},
situationRoute: function() {
var view = new views.Situation();
var target = 'Situation';
this.layout.setContent(view);
},
videoRoute: function() {
var view = new views.Video();
var target = 'Video';
this.layout.setContent(view);
},
cultureRoute: function(){
var view = new views.Culture();
var target = 'Culture';
this.layout.setContent(view);
}
});
var router = new app.Router();
Backbone.history.start();
})();
view.js(我的来源)
var app = app || {};
(function() {
'use strict';
//views linitalize
var views = app.view = app.view || {};
views.Application = Backbone.View.extend({
initialize: function() {
this.$content = this.$('#container');
//this.$loading = this.$('#loading');
},
setContent: function(view, target) {
var content = this.content;
this.renderSubpage();
if (content) content.remove();
content = this.content = view;
this.$content.html(content.render().el);
},
showSpinner: function() {
this.$loading.show();
},
hideSpinner: function() {
this.$loading.hide();
},
renderSubpage: function(target){
var target = target;
var templateName = target;
var tmpl_dir = '../assets/static';
var tmpl_url = tmpl_dir + '/' + templateName + '.html';
var tmpl_string = '';
$.ajax({
url: tmpl_url,
method: 'GET',
async: false,
dataType : html,
success: function (data) {
tmpl_string = data;
}
});
var template = _.template(tmpl_string);
this.$el.html(template);
return this;
}
});
views.Home = Backbone.View.extend({
render: function(html) {
return this;
//how to get return result? in parent object?
}
});
views.Stuation = Backbone.View.extend({
render: function() {
var template = _.template("<strong><% print('Hello ' + page); %></strong>");
var pageTxt = {page: "About"};
var html = template(pageTxt);
this.$el.html(html);
return this;
}
});
views.Video = Backbone.View.extend({
render: function() {
var template = _.template("<strong><% print('Hello ' + page); %></strong>");
var pageTxt = {page: "Contact"};
var html = template(pageTxt);
this.$el.html(html);
return this;
}
});
views.Culture = Backbone.View.extend({
render: function() {
var template = _.template("<strong><% print('Hello ' + page); %></strong>");
var pageTxt = {page: "Contact"};
var html = template(pageTxt);
this.$el.html(html);
return this;
}
});
})();
renderSubpage:函数(目标)最初位于源下。
views.Home = Backbone.View.extend({
render: function(html) {
var templateName = home;
var tmpl_dir = '../assets/static';
var tmpl_url = tmpl_dir + '/' + templateName + '.html';
var tmpl_string = '';
$.ajax({
url: tmpl_url,
method: 'GET',
async: false,
dataType : html,
success: function (data) {
tmpl_string = data;
}
});
var template = _.template(tmpl_string);
this.$el.html(template);
return this;
}
});
我不需要重复代码。
View .Home = templateName = 'home';
~~
情况 = tamplateName = '情况';
~~
如何解决？
最佳答案
var app = app || {};
(function() {
'use strict';
//views linitalize
var views = app.view = app.view || {};
views.Application = Backbone.View.extend({
initialize: function() {
this.$content = this.$('#container');
//this.$loading = this.$('#loading');
},
setContent: function(view, target) {
var content = this.content;
var subUrl = this.target;
if (content) content.remove();
//if (content || target) content.remove()target.remove();
content = this.content = view;
subUrl = this.target = target;
var templateName = subUrl;
var tmpl_dir = '../assets/static';
var tmpl_url = tmpl_dir + '/' + templateName + '.html';
var tmpl_string = '';
$.ajax({
url: tmpl_url,
method: 'GET',
async: false,
dataType : 'html',
success: function (data) {
tmpl_string = data;
}
});
console.log(tmpl_string);
this.$content.html(content.render(tmpl_string).el);
},
showSpinner: function() {
this.$loading.show();
},
hideSpinner: function() {
this.$loading.hide();
}
});
views.Home = Backbone.View.extend({
render: function(templateName) {
var template = _.template(templateName);
this.$el.html(template);
return this;
}
});
我解决了该问题，使用ajax调用subUrl使用函数参数并抛出子对象，然后子对象呈现此模板字符串。
关于javascript - 主干中的动态加载模板和对象之间的通信，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/41533209/