c++ - 如何从 HBITMAP 创建 Gdiplus::Bitmap，保留 alpha channel 信息？

Question

当我使用 Bitmap::FromHBITMAP 函数创建一个新的 Gdiplus::Bitmap 时， 生成的 Bitmap 是不透明的 - 原始 HBITMAP 的部分透明度都没有保留。

有没有一种方法可以从 HBITMAP 创建一个 Gdiplus::Bitmap 来传递 alpha channel 数据？

Answer 1

我认为工作代码比指令更有用，所以:

#include <GdiPlus.h>
#include <memory>

Gdiplus::Status HBitmapToBitmap( HBITMAP source, Gdiplus::PixelFormat pixel_format, Gdiplus::Bitmap** result_out )
{
  BITMAP source_info = { 0 };
  if( !::GetObject( source, sizeof( source_info ), &source_info ) )
    return Gdiplus::GenericError;

  Gdiplus::Status s;

  std::auto_ptr< Gdiplus::Bitmap > target( new Gdiplus::Bitmap( source_info.bmWidth, source_info.bmHeight, pixel_format ) );
  if( !target.get() )
    return Gdiplus::OutOfMemory;
  if( ( s = target->GetLastStatus() ) != Gdiplus::Ok )
    return s;

  Gdiplus::BitmapData target_info;
  Gdiplus::Rect rect( 0, 0, source_info.bmWidth, source_info.bmHeight );

  s = target->LockBits( &rect, Gdiplus::ImageLockModeWrite, pixel_format, &target_info );
  if( s != Gdiplus::Ok )
    return s;

  if( target_info.Stride != source_info.bmWidthBytes )
    return Gdiplus::InvalidParameter; // pixel_format is wrong!

  CopyMemory( target_info.Scan0, source_info.bmBits, source_info.bmWidthBytes * source_info.bmHeight );

  s = target->UnlockBits( &target_info );
  if( s != Gdiplus::Ok )
    return s;

  *result_out = target.release();

  return Gdiplus::Ok;
}