javascript - 断言测试函数成功或失败测试

Question

我试图在这里创建一个断言测试函数，将实际值和预期值严格相等(而不是类型转换)进行比较。

以下是一个成功案例的示例:

function multiplyByTwo(n) {
  return n * 2;
}
var output = multiplyByTwo(2); // returns 4
assertTesting(output, 4, 'it doubles 2 to 4');
// console output:
// passed

这是一个失败的例子:

function multiplyByTwo(n) {
  return (n * 2) + 1; // an incorrect implementation
}
var output = multiplyByTwo(2); // returns 5
assertTesting(output, 4, 'it doubles 2 to 4');
// console output:
// FAILED [it doubles 2 to 4] Expected "4", but got "5"

这是到目前为止我的代码:

var output;

function multiplyByTwo(n) {
  output = n * 2;
  return output;
}

function assertTesting (actual, expected, testName) {
  if(actual === ouput && expected === testName){
    return "SUCCESS" + [testname] + "Expected" + expected + "," "but got" + actual;
  }
}

知道如何获得我需要的确切输出吗？请帮忙。

Answer 1

我猜应该是这样的:

function assertEqual(actual, expected, testName) {
  if(actual !== expected){
    console.error( "FAIL [" + testname + "] Expected \"" + expected + ", \" but got \"" + actual + "\"");
  } else {
    console.info( "SUCCESS [" + testname + "]");
  }
}