所以我试图通过在 JS 中创建大部分代码来更好地练习 JS 和 Jquery。 我试图搜索并实现这个方法,但空手而归。 我将附上原始 HTML,然后在 Jquery 中尝试:
HTML
<div class="mainContainer col-md-12 col-xs-12">
<div class="checkBoxes">
<span class="recipePicContainer">
<img class="recipe" src="../images/grasshopper-cocktail.jpg" alt="Cocktail">
<div>Cocktail</div>
</span>
<ul class="recipes">
<li class="ingredient"><input type="checkbox"> ingredient 1</li>
<li class="ingredient"><input type="checkbox"> ingredient 2</li>
<li class="ingredient"><input type="checkbox"> ingredient 3</li>
<li class="ingredient"><input type="checkbox"> ingredient 4</li>
<li class="instructions">Lorem ipsum dolor sit amet, consectetur adipiscing elit.</li>
</ul>
</div>
Jquery
var main = function() {
$(document).ready(function () {
var $checkBoxes = $('<div>',{class: "checkBoxes"});
var $recipePicContainer = $('<span>', {class: "recipePicContainer"});
var $img = document.getElementById("recipe");
var $div = $('<div></div>');
$('.mainContainer').append($checkBoxes);
$($checkBoxes).append($recipePicContainer);
$($recipePicContainer).append($img);
$($recipePicContainer).append($div).append('Cocktail');
$('.recipePicContainer').click(function () {
$(this).next('.recipes').toggle("slow").toggleClass('selected');
});
});
};
$(document).ready(main);
谢谢!
最佳答案
解决方案在这里 https://jsfiddle.net/xg5r72xt/
$(document).ready(function () {
var $checkBoxes = $('<div>',{class: "checkBoxes"});
var $recipePicContainer = $('<span>', {class: "recipePicContainer"});
var $img = document.getElementsByClassName("recipe");
console.log($img);
var $div = $('<div></div>');
$('.mainContainer').append($checkBoxes);
$($checkBoxes).append($recipePicContainer);
$($recipePicContainer).append($img);
$($recipePicContainer).append($div).append('Cocktail');
$('.recipePicContainer').click(function () {
$(this).next('.recipes').toggle("slow").toggleClass('selected');
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="mainContainer col-md-12 col-xs-12">
<div class="checkBoxes">
<span class="recipePicContainer">
<img class="recipe" src="../images/grasshopper-cocktail.jpg" alt="Cocktail">
<div>Cocktail</div>
</span>
<ul class="recipes">
<li class="ingredient"><input type="checkbox"> ingredient 1</li>
<li class="ingredient"><input type="checkbox"> ingredient 2</li>
<li class="ingredient"><input type="checkbox"> ingredient 3</li>
<li class="ingredient"><input type="checkbox"> ingredient 4</li>
<li class="instructions">Lorem ipsum dolor sit amet, consectetur adipiscing elit.</li>
</ul>
</div>
代码问题
var $img = document.getElementById("菜谱");
更改了代码说明 具有 ID 菜谱的元素不存在,而是我使用了图像标记中的“菜谱”类。
我相信这是问题之一。
关于javascript - 将 HTML 元素翻译成 Jquery 但看不到它们,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45129056/