javascript - 多个 Gulp 任务等待另一个任务

Question

我需要构建一系列 Gulp 任务，如下所示:

任务1 -> 任务2A、任务2B、任务2C -> 任务3，

其中任务 2A、2B、2C 并行运行(但任务 1 应该在之前完成，并且只完成一次)。

我尝试过的:

gulp.task('Task1', []);

gulp.task('Task2A', ['Task1']);

gulp.task('Task2B', ['Task1']);

gulp.task('Task2C', ['Task1']);

gulp.task('Task3', ['Task2A', 'Task2B', 'Task2C']);

看起来是有效的，但我不确定，它是否保证Task1只会执行1次，还是可以触发多次？

谢谢。

Answer 1

也许最简单的方法(不使用 gulp4.0)是 run-sequence plugin .

对于您的情况:

var runSequence = require('run-sequence');

gulp.task('build', function(callback) {
   runSequence( 'Task1',
               ['Task2A', 'Task2B', 'Task2C'],
                'Task3',
                callback);
});

确保所有任务中都有 return 语句。

Please Note

This was intended to be a temporary solution until the release of gulp 4.0 which should have support for defining task dependencies similarly.

Given that Gulp 4 appears to never be fully released, take that for what you will. Be aware that this solution is a hack, and may stop working with a future update to gulp.