Javascript - 如何随机重定向到网站而不重复？

Question

我想制作一个tampermonkey脚本，随机重定向到网站而不重复。查看完所有网站后，我希望出现一个警报，通知脚本已完成。

我使用了这里的脚本( How to redirect to one out of given set of sites? )，但它重复了网站。

我应该如何处理这个问题？

// ==UserScript==
// @name        Cat slideshow
// @match       https://i.imgur.com/homOZTh.jpg
// @match       https://i.imgur.com/NMDCQtA.jpg
// @match       https://i.imgur.com/iqm9LoG.jpg
// ==/UserScript==

var urlsToLoad  = [
    'https://i.imgur.com/homOZTh.jpg',
    'https://i.imgur.com/NMDCQtA.jpg',
    'https://i.imgur.com/iqm9LoG.jpg',
];

setTimeout (GotoRandomURL, 4000);

function GotoRandomURL () {
    var numUrls     = urlsToLoad.length;
    var urlIdx      = urlsToLoad.indexOf (location.href);
    if (urlIdx >= 0) {
        urlsToLoad.splice (urlIdx, 1);
        numUrls--;
    }

    urlIdx          = Math.floor (Math.random () * numUrls);
    location.href   = urlsToLoad[urlIdx];
} 

Answer 1

编辑:修复了代码的 math.random 部分。

这应该有效。我只是复制该数组，然后在导航到该 url 后，从复制的数组中删除该 url。它只会在遍历所有 url 并重新开始后重复一个 url。

const urlsToLoad = [
  'https://i.imgur.com/homOZTh.jpg',
  'https://i.imgur.com/NMDCQtA.jpg',
  'https://i.imgur.com/iqm9LoG.jpg',
];

let copyOfUrlsToLoad = [];

setTimeout(goToRandomURL, 4000);

function goToRandomURL () {
  if (copyOfUrlsToLoad.length === 0) {
    copyOfUrlsToLoad = urlsToLoad;
  }
  urlIdx = getRandomInt(0, copyOfUrlsToLoad.length);
  location.href = copyOfUrlsToLoad[urlIdx];
  copyOfUrlsToLoad.splice(urlIdx, 1);
}

// This function comes from https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Math/random#Getting_a_random_integer_between_two_values
function getRandomInt(min, max) {
    min = Math.ceil(min);
    max = Math.floor(max);
    return Math.floor(Math.random() * (max - min)) + min; //The maximum is exclusive and the minimum is inclusive
}

如果您想在新选项卡或窗口中打开网址，this answer表示将 location.href 行替换为以下内容:

window.open(copyOfUrlsToLoad[urlIdx], '_blank');