我在Google和StackOverflow上做了很多研究,但我无法解决这个问题(这就是为什么这个问题不重复): 我有一个 js 函数,在单击时调用(工作)。通过这个函数,我试图调用一个 PHP 脚本来执行...但它没有反应...请告诉我出了什么问题(完整的解决方案将不胜感激...)
<小时/>PHP 代码:
<?php
$servername = "bot-sam.lima-db.de:3306";
$username = "USER379138";
$password = "pwd";
$dbname = "db_379138_1";
$q = $_POST['q'];
$a = $_POST['a'];
function alert($msg) {
echo "<script type='text/javascript'>alert('$msg');</script>";
}
echo $q . $a;
// echo and alert are not opening so i think the php script isn't executing
alert("question is " . $q);
alert("answer is " . $a);
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "INSERT INTO knowledge_base ('question', 'answer')
VALUES ($q, $a)";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
?>
<小时/>
JavaScript 函数(正确调用;jQuery 工作):
function myfunc() {
var question = "test1";
var answer = "test2";
$.ajax({
url: 'phpscript.php',
type: 'POST',
data: {q: question, a: answer},
dataType: 'json',
sucess: console.log("SQL entry made")
});
}
很抱歉问这么简单的问题,但我无法解决问题......
最佳答案
尝试使用下面的代码
function myfunc() {
var question = "test1";
var answer = "test2";
$.ajax({
url: 'phpscript.php',
type: 'POST',
data: {q: question, a: answer},
dataType: 'json',
success: function(result) {
console.log(result);
}
});
}
关于javascript - 从 JavaScript 使用参数调用 PHP 脚本,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48813401/