javascript - 如何在 Javascript 中将一个函数的响应提供给另一个函数？

Question

我有一堂这样的课:

class MyModule {
  constructor() {
    this.val = 0;
  }

  foo(a,b) {
    this.val = a+b;
    return this.val
  } 

  bar() {
    return this.val + 10
  }

  silly() {
    return __isGreaterThan(50)
  }
}

现在我希望能够以以下不同的方式使用上述类，如下所示 res1 和 res2。

const xyz = require('myModule');

const res1 = xyc.foo(5,10).bar().silly();
const res2 = xyz.foo(5,10);

console.log(res1) // Outputs --> false
console.log(res2) // Outputs --> 15

Answer 1

这是一个示例，只需对代码进行最小的更改即可输出您想要的内容

注意:在您的代码中，您永远不会创建 MyClass 的实例，我认为您需要了解类的工作原理

class MyModule {
  constructor() {
    this.val = 0;
  }

  foo(a,b) {
    this.val = a+b;
    return this;
  } 

  bar() {
    this.val += 10;
    return this;
  }

  silly() {
    return this.val > 50;
  }
}
// in a separate file, you'd do something like
//
// const MyModule = require('myModule');
//
// obviously, won't work in this snippet, but that's the only difference 
// with what your real world code would need

const xyc = new MyModule();
const xyz = new MyModule();
const res1 = xyc.foo(5,10).bar().silly();
const res2 = xyz.foo(5,10).val; // note: you need to get the `val` property

console.log(res1) // Outputs --> false
console.log(res2) // Outputs --> 15