javascript - 如果键存在，则使用键和值形成 JSON

Question

我有一个 JSON 结构，如下所示:

    [  
   {  
      "name":"angelinas"
   },
   {  
      "name":"besuto"
   },
   {  
      "name":"catch",
      "cuisine":"Japanese"
   },
   {  
      "name":"center cut"
   },
   {  
      "name":"fedora"
   },
   {  
      "name":"Habanero",
      "cuisine":"Mexican"
   },
   {  
      "name":"Indies"
   },
   {  
      "name":"new"
   },
   {  
      "name":"RazINN"
   },
   {  
      "name":"restaurantTestVenue779"
   },
   {  
      "name":"restaurantTestVenue9703"
   },
   {  
      "name":"Salsa ",
      "cuisine":"Mexican"
   },
   {  
      "name":"Sushi Place",
      "cuisine":"Japanese"
   },
   {  
      "name":"The Ashoka"
   },
   {  
      "name":"The Poboys"
   },
   {  
      "name":"the shogun"
   },
   {  
      "name":"vinyard view"
   }
]

使用上面的 JSON，我想确定菜肴是否与餐厅相关。如果是，我想构建一个 JSON 结构，如下所示:

[  
   {  
      "Mexican":{  
         "venueNames":[  
            "Habanero",
            "Salsa"
         ]
      }
   },
   {  
      "Japanese":{  
         "venueNames":[  
            "Sushi Place",
            "catch"
         ]
      }
   }
]

尝试使用 for 循环和 .hasProperty 构建 JSON，但不太成功。

Answer 1

这就是你可以做的! 首先迭代数据并使用方法“hasOwnProperty”检查菜系是否存在，如果存在，则检查您的菜系对象是否具有该菜系，如果存在则将其添加到其中。

const data = [{
        "name": "angelinas"
    },
    {
        "name": "besuto"
    },
    {
        "name": "catch",
        "cuisine": "Japanese"
    },
    {
        "name": "center cut"
    },
    {
        "name": "fedora"
    },
    {
        "name": "Habanero",
        "cuisine": "Mexican"
    },
    {
        "name": "Indies"
    },
    {
        "name": "new"
    },
    {
        "name": "RazINN"
    },
    {
        "name": "restaurantTestVenue779"
    },
    {
        "name": "restaurantTestVenue9703"
    },
    {
        "name": "Salsa ",
        "cuisine": "Mexican"
    },
    {
        "name": "Sushi Place",
        "cuisine": "Japanese"
    },
    {
        "name": "The Ashoka"
    },
    {
        "name": "The Poboys"
    },
    {
        "name": "the shogun"
    },
    {
        "name": "vinyard view"
    }
]

let cuisines = {};


for (const resturant of data) {
    if (resturant.hasOwnProperty('cuisine')) {

        if (cuisines.hasOwnProperty(resturant.cuisine)) {
            cuisines[resturant.cuisine].venueNames.push(resturant.name);
        } else {
            cuisines[resturant.cuisine] = {
                venueNames: [resturant.name]
            };
        }
    }
}