我正在尝试正确理解 Promise。
我有一个 sleep 函数,如果我传递一个时间,它就会延迟执行它。我想按顺序执行所有内容。
问题:
1: 然而,有时我的“完成”甚至在 promise 完全兑现之前就被告知了。有人可以解释一下我的代码中的错误在哪里吗?
2:我可以在这里使用 async wait 而不是 Promise 吗?如果是的话怎么办?
我的尝试:
/* Do the following:
2- creating sequential promise, by wait for 1s, 2s and 3s sequentially. And showing result for each promise is done.
3- creating parallel promise, by wait for 1s, 2s and 3s parallelly. And showing result when all promise is done.
4- creating mixed promise, by wait 1s, 2s squentially, after then wait for 3s, 4s, 5s parallelly.
5- createing sequential promise, by wait for 1s, undefined and 3s sequentially. catch the error.
6- createing sequential promise, by wait for 5 different numbers, with random number as input.
*/
// Sleep takes time and returns time+1
const sleep = (time) => {
return new Promise((resolve, reject) => {
setTimeout(() => {
console.log(`Resolving: ${time}+1`);
resolve(time+1);
}, time*1000);
});
}
// Generate Random number within a range.
const randomNumber = (min=1, max=8) => {
return Math.floor(Math.random() * (max-min+1) + min);
} // -5~5
console.log(
sleep(randomNumber())
.then(sleep(randomNumber()))
.then(sleep(randomNumber()))
.then(sleep(randomNumber()))
.then(sleep(randomNumber()))
.then((e)=> {
console.log("Done", e); // Done called when all promises are done.
})
)
最佳答案
.then
接受一个函数参数,而不是Promise
。改变你的
.then(sleep(randomNumber()))
发送至
.then(() => sleep(randomNumber)
以便将函数放入Promise
链中,当前面的.then
解析时将调用该函数。否则,一旦 Promise 链创建,每个 sleep(randomNumber())
都会立即被调用。
/* Do the following:
2- creating sequential promise, by wait for 1s, 2s and 3s sequentially. And showing result for each promise is done.
3- creating parallel promise, by wait for 1s, 2s and 3s parallelly. And showing result when all promise is done.
4- creating mixed promise, by wait 1s, 2s squentially, after then wait for 3s, 4s, 5s parallelly.
5- createing sequential promise, by wait for 1s, undefined and 3s sequentially. catch the error.
6- createing sequential promise, by wait for 5 different numbers, with random number as input.
*/
// Sleep takes time and returns time+1
const sleep = (time) => {
return new Promise((resolve, reject) => {
setTimeout(() => {
console.log(`Resolving: ${time}+1`);
resolve(time+1);
}, time*1000);
});
}
// Generate Random number within a range.
const randomeNumber = (min=1, max=8) => {
return Math.floor(Math.random() * (max-min+1) + min);
} // -5~5
console.log(
sleep(randomeNumber())
.then(() => sleep(randomeNumber()))
.then(() => sleep(randomeNumber()))
.then(() => sleep(randomeNumber()))
.then(() => sleep(randomeNumber()))
.then((e)=> {
console.log("Done", e); // Done called when all promises are done.
})
)
要并行运行它们并在全部解决后运行某些内容,请使用 Promise.all
:
Promise.all([
sleep(randomeNumber()),
sleep(randomeNumber()),
sleep(randomeNumber()),
sleep(randomeNumber()),
sleep(randomeNumber())
])
.then(() => console.log('all done'));
关于javascript - 顺序 promise 的问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52640581/