这里我有 data.payload 和 folderObjs 我想将 data.payload 合并到 folderObjs 中folderObjs 的 folderid == data.payload[i].upperfolderid 看到 patternObj 控制台输入我想要的结果
我尝试使用 concat，但它合并到 folderObjs 数组中，而不是合并到特定的 folderObjs folderid
data.payload
(2) [{…}, {…}]
0: { folderid: 903, folderName: "f11", upperfolderid: 899}
1: { folderid: 904, folderName: "f22", upperfolderid: 899}
folderObjs
(4) [{…}, {…}, {…}, {…}]
0: { folderid: 899, folderName: "f1", upperfolderid: 122}
1: { folderid: 900, folderName: "f2", upperfolderid: 122}
2: { folderid: 901, folderName: "f3", upperfolderid: 122}
3: { folderid: 902, folderName: "f4", upperfolderid: 122}
// TS
folderObjs : Folder[] = [];
patternObj : Pattern[] = [];
this.patterObj = this.folderObjs.concat(data.payload);
console.log(this.patternObj);
// This type result I want
0: {folderid: 899, folderName: "f1,upperfolderid: 122,
{0: {folderid: 903, folderName: "f11", upperfolderid: 899}
1: {folderid: 904, folderName: "f22", upperfolderid: 899}
}
}
1: {folderid: 900, folderName: "f2",upperfolderid: 122}
2: {folderid: 901, folderName: "f3",upperfolderid: 122}
3: {folderid: 902, folderName: "f4",upperfolderid: 122}
最佳答案
我希望下面的例子能有所帮助。
const result = this.folderObjs.map(val => {
return Object.assign({}, val, this.payload.filter(v => v.upperfolderid === val.folderid));
});
console.log(result);
关于javascript - 如何合并多维数组？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/53827069/