javascript - 计算值未进入for循环

Question

我需要计算 var packprice + var packprices + var ala 哪个进入 for 循环。我在控制台中获取了所有值，但在 tprice 中没有获取加法。请帮忙。

$( "#get_total" ).click(function() {
    alert('calculation pending');
    var idSelector = function() { return this.value; };
    var packprices = 0;
    var packprice = 0;
    var c = $(":checkbox:checked").map(idSelector).get();

    for (var i = 0; i < c.length; i++) {
        // console.log(c[i]);
        // console.log(parseInt($(".longduration_price" + c[i]).val()));
        if($(".duration_status" + c[i]).is(':checked'))
        {
            var packprice = !isNaN(parseInt($(".longduration_price" + c[i]).val())) ? parseInt($(".longduration_price" + c[i]).val()) : 0 ;
            console.log(packprice);
        }else{
            var packprices = !isNaN(parseInt($(".packpriceone" + c[i]).val())) ? parseInt($(".packpriceone" + c[i]).val()) : 0 ;
            console.log(packprices); 
        }
        var ala = parseInt($("#alacartprice").val());
        var tprice = packprice + packprices + ala;
    }

    console.log(tprice);

    $("#totalprice").val(tprice);
});

Answer 1

您需要在循环外部声明 tprice 并将结果添加到 tprice 中，如下所示。

$( "#get_total" ).click(function() {
alert('calculation pending');
var idSelector = function() { return this.value; };
var packprices = 0;
var packprice = 0;
var c = $(":checkbox:checked").map(idSelector).get();
var tprice = 0;
for (var i = 0; i < c.length; i++) {
    // console.log(c[i]);
    // console.log(parseInt($(".longduration_price" + c[i]).val()));
    if($(".duration_status" + c[i]).is(':checked'))
    {
        var packprice = !isNaN(parseInt($(".longduration_price" + c[i]).val())) ? parseInt($(".longduration_price" + c[i]).val()) : 0 ;
        console.log(packprice);
    }else{
        var packprices = !isNaN(parseInt($(".packpriceone" + c[i]).val())) ? parseInt($(".packpriceone" + c[i]).val()) : 0 ;
        console.log(packprices); 
    }
    var ala = parseInt($("#alacartprice").val());
    tprice += packprice + packprices + ala;
}

console.log(tprice);

$("#totalprice").val(tprice);
});