javascript - 检测字符串数组中的异常值 - VanillaJS 和 parseInt

Question

给定一串偶数和奇数，找出唯一的偶数或唯一的奇数。

示例: 检测离群值(“2 4 7 8 10”);//=> 2 - 第三个数字是奇数，而其余数字是偶数

即使我已经将所有内容都转换为数字，为什么我还需要再次解析Int(evens)？

function detectOutlierValue(str) {
  //array of strings into array of numbers
  newArr = str.split(" ").map(x => parseInt(x))

  evens = newArr.filter(num => num % 2 === 0)
  odds = newArr.filter(num => num % 2 !== 0)

  //if the array of evens has just 1 item while the majority is odds, we want to return the position of that item from the original string.

  if (evens.length === 1) {
    return newArr.indexOf(parseInt(evens)) 
  } else {
    return newArr.indexOf(parseInt(odds)) 
  }
}

Answer 1

这是因为 evens 和 odds 在您将它们放入 indexOf 时是数组。尝试用每个数组的第一个值替换最后两行:

function detectOutlierValue(str) {
  //array of strings into array of numbers
  newArr = str.split(" ").map(x => parseInt(x))

  evens = newArr.filter(num => num % 2 === 0)
  odds = newArr.filter(num => num % 2 !== 0)

  //if the array of evens has just 1 item while the majority is odds, we want to return the position of that item from the original string.

  if (evens.length === 1) {
    return newArr.indexOf(evens[0]) 
  } else {
    return newArr.indexOf(odds[0]) 
  }
}