javascript - 如何从对象中的特定参数从我的对象中找到唯一的对象

Question

var links = {
    1:{source: 0, target: 1},
    2:{source: 0, target: 2},
    3:{source: 0, target: 3},
    4:{source: 0, target: 4},
    5:{source: 0, target: 1},
    6:{source: 0, target: 4}  
};

这是我的数据，我想通过参数从中获得唯一的对象:目标就像

var result= {
    1:{source: 0, target: 1},
    2:{source: 0, target: 2},
    3:{source: 0, target: 3},
    4:{source: 0, target: 4},
};

Answer 1

您可以通过将 Array.from 与 Set 一起使用来删除重复项，而无需下划线，如下所示:

const links = [{source: 0, target: 1}, {source: 0, target: 2}, {source: 0, target: 3}, {source: 0, target: 4}, {source: 0, target: 1}, {source: 0, target: 4}]

const res = Array.from(new Set(links.map(JSON.stringify)), JSON.parse);
console.log(res);

但是，如果target 与另一个target 属性相同，并且对象中的另一个属性不同(即它将删除重复的对象)，则上述内容将保留元素。

要根据数组中的键删除特定的重复项，可以使用 .reduce:

const links = [{source: 0, target: 1}, {source: 0, target: 2}, {source: 0, target: 3}, {source: 0, target: 4}, {source: 0, target: 1}, {source: 0, target: 4}];

const res = Object.values(links.reduce((acc, obj) => {
  const {target} = obj;
  acc[target] = obj;
  return acc;
}, {}));

console.log(res);