javascript - 如何在集合中过滤mongoDB中的查询

Question

我正在尝试在 mongoDB 中进行过滤，但没有得到预期的输出。我正在使用$elemMatch但仍然没有达到预期。

代理收藏

[

  {
    "_id": "5d402d36035f3063657240ac",
    "name": "test agency",
    "msisdn": "99961110278",
    "apps": [
      {
        "pincodes": [
          "135001",
          "122018"
        ],
        "_id": "5d402d36035f3063657240ae",
        "name": "DSB"
      },
      {
        "pincodes": [
          "135001",
          "122017"
        ],
        "_id": "5d402d36035f3063657240ad",
        "name": "DBH"
      }
    ],
    "__v": 0
  }
]

在 shell 上查询

db.Agency.find({'apps':{$elemMatch:{name: {$regex: 'DSB', $options: 'i'} ,pincodes: { $in : ['135001','134002']}}}})

获取输出

[
{
  "_id" : "5d401d4aba592260507479d2",
  "name" : "test agency",
  "msisdn" : "99961110278",
  "apps" : [
    {
      "pincodes" : [
        "135001",
        "122017"
      ],
      "_id" : "5d401d4aba592260507479d3",
      "name" : "DSB"
    }
  ],
  "__v" : 0
}
,
{
  "_id" : "5d402249035f3063657240a9",
  "name" : "test agency",
  "msisdn" : "99961110278",
  "apps" : [
    {
      "pincodes" : [
        "135001",
        "122017"
      ],
      "_id" : "5d402249035f3063657240ab",
      "name" : "DSB"
    },
    {
      "pincodes" : [
        "135001",
        "122017"
      ],
      "_id" : "5d402249035f3063657240aa",
      "name" : "DBH"
    }
  ],
  "__v" : 0
}
,
{
  "_id" : "5d402d36035f3063657240ac",
  "name" : "test agency",
  "msisdn" : "99961110278",
  "apps" : [
    {
      "pincodes" : [
        "135001",
        "122018"
      ],
      "_id" : "5d402d36035f3063657240ae",
      "name" : "DSB"
    },
    {
      "pincodes" : [
        "135001",
        "122017"
      ],
      "_id" : "5d402d36035f3063657240ad",
      "name" : "DBH"
    }
  ],
  "__v" : 0
}]

预期输出

[
{
  "_id" : "5d401d4aba592260507479d2",
  "name" : "test agency",
  "msisdn" : "99961110278",
  "apps" : [
    {
      "pincodes" : [
        "135001",
        "122017"
      ],
      "_id" : "5d401d4aba592260507479d3",
      "name" : "DSB"
    }
  ],
  "__v" : 0
}
,
{
  "_id" : "5d402249035f3063657240a9",
  "name" : "test agency",
  "msisdn" : "99961110278",
  "apps" : [
    {
      "pincodes" : [
        "135001",
        "122017"
      ],
      "_id" : "5d402249035f3063657240ab",
      "name" : "DSB"
    }
  ],
  "__v" : 0
}
,
{
  "_id" : "5d402d36035f3063657240ac",
  "name" : "test agency",
  "msisdn" : "99961110278",
  "apps" : [
    {
      "pincodes" : [
        "135001",
        "122018"
      ],
      "_id" : "5d402d36035f3063657240ae",
      "name" : "DSB"
    }
  ],
  "__v" : 0
}]

Answer 1

您也可以通过 $group 和 $match 以另一种方式进行操作。

db.getCollection('test').aggregate([
  {$match: {"apps.name": {$regex: 'DSB', $options: 'i'}}}, // Return only data which name is DSB
  {$unwind: "$apps"}, // Convert array to object (To remove DTH data in same document)
  {$match: {"apps.name": {$regex: 'DSB', $options: 'i'}, // Again filter with DSB and pincodes "apps.pincodes": { $in : ['135001','134002']}}},
  {$group: { // Finall group it again. So we will have only DSB related data
    _id: "$_id",
    name: {$first: "$name"},
    msisdn: {$first: "$msisdn"},
    __v: {$first: "$__v"},
    apps: {$push: "$apps"}
  }}
])