javascript - 打开新标签页后 Chrome 扩展程序退出运行 javascript

Question

我正在尝试制作一个 Chrome 扩展，它在一个选项卡中启动，并在打开几个新选项卡时继续运行。但是，它仅启动 1 个新选项卡，而不是指定的 5 个选项卡，因为脚本停止运行。

重要部分:

function launch (url, name, callOnLoad) {
  window.open(url, name)
    .addEventListener(
      "load",
      callOnLoad,
      { once: true, passive: true }
    );
}
async function launchProcess (taburl) {
  const sleep3 = { then(resolve) { setTimeout(resolve, 250); } };
  for (let i = 2; i < 7; ++i) {
    launch(taburl, "tab" + i, proceed);
    await sleep3;
  }
}
launchProcess(taburl) //Taburl is acquired by running a chrome query to find the last active site.

整个脚本:

function proceed (evt) {
  console.log("A window has been loaded");
  console.log(evt);
//End of execution
}

async function launchProcess (taburl) {
  const sleep3 = { then(resolve) { setTimeout(resolve, 250); } };
  for (let i = 2; i < 7; ++i) {
    launch(taburl, "tab" + i, proceed);
    await sleep3;
  }
}

async function timer(time) { //timer() is only used if the user activates it, so you can ignore it atm
    const sleep = { then(resolve) { setTimeout(resolve, 15000); } };
    var date = new Date();
    var timestamp = date.getTime();
    timestamp = timestamp + 60000
    while (time > timestamp) {
        date = new Date();
        timestamp = date.getTime();
        timestamp = timestamp + 60000
        await sleep;
    }
    const sleep2 = { then(resolve) { setTimeout(resolve, 250); } };
    var excttimestamp = new Date();
    while (time > excttimestamp) {
        excttimestamp = new Date();
        await sleep2;
    }
    launchProcess().then(console.log, console.error);
}

PS:如果有人有一些关于如何使timer()更高效的线索，我们非常欢迎帮助:)

我希望该功能“启动”多个选项卡并休眠，然后打开另一个选项卡并运行其他未提及的功能。相反，它只打开一个然后退出。

Answer 1

我为自己找到了解决方案: chrome.tabs.create({url: 'http://www.google.com', active: false}); 在 chrome 上打开一个新选项卡，但不关注它，因此弹出窗口保持不变，代码继续运行:)