我正在为应用程序实现一个设置页面。对于每个设置,我都实现了一个具有启用(绿色)或禁用(红色)状态的 slider 。但父级的设置是只读的,并且是根据其子级的值计算的。
父级的设置推导如下:如果所有子级都是红色,则父级保持红色;如果全部都是绿色,则父级保持绿色;如果至少一个 child 是绿色的,那么 parent 保持灰色(待定)。
这些设置按如下方式分组:
父功能 1:(只读切换)
Setting 1 (Toggle)
Setting 2 (Toggle)
父功能 2:(只读切换)
Setting 1 (Toggle)
Setting 2 (Toggle)
最后还有一个按钮,可以为我提供所有 parent 和 child 的综合值。但到目前为止,我只能与一位 parent 和 2 个 child 一起做。
有人可以帮助提供一种方法,将所有设置的综合值放在一个位置(例如配置所有这些设置的 super 父组件)。
为此,我使用react-multi-toggle作为此切换开关。
非常感谢您的帮助。
代码沙箱:https://codesandbox.io/s/react-multi-toggle-solution-perfect-v9bi5
应用程序
import React from "react";
import ChildSwitch from "./ChildSwitch";
import ParentSwitch from "./ParentSwitch";
export default class App extends React.Component {
constructor(props) {
super(props);
this.state = {
parentVal: "disabled",
switch1Val: "enabled",
switch2Val: "disabled"
};
}
componentDidMount() {
this.setParentSwitchValue();
}
onGetChildSwitchValues = () => {
console.log(this.state);
};
setChildSwitchValue = (whichSwitch, selected) => {
this.setState(
prevState => ({ ...prevState, [whichSwitch]: selected }),
this.setParentSwitchValue
);
};
setParentSwitchValue = () => {
const { switch1Val, switch2Val } = this.state;
const switchStates = [switch1Val, switch2Val];
let parent = "pending";
if (switchStates.every(val => val === "enabled")) {
parent = "enabled";
}
if (switchStates.every(val => val === "disabled")) {
parent = "disabled";
}
this.setState(prevState => ({ ...prevState, parentVal: parent }));
};
render() {
const { parentVal, switch1Val, switch2Val } = this.state;
return (
<>
<div className="boxed">
Parent Setting 1 :{" "}
<ParentSwitch
parentSwitch={parentVal}
onSelect={this.setParentSwitchValue}
/>
Setting 1:
<ChildSwitch
switchName={"switch1Val"}
selected={switch1Val}
onSelect={this.setChildSwitchValue}
/>
Setting 2:
<ChildSwitch
switchName={"switch2Val"}
selected={switch2Val}
onSelect={this.setChildSwitchValue}
/>
</div>
<button onClick={this.onGetChildSwitchValues}>Get All Values</button>
</>
);
}
}
子设置
import MultiToggle from "react-multi-toggle";
import React from "react";
export default class ChildSwitch extends React.Component {
constructor(props) {
super(props);
this.state = {
options: [
{
displayName: "Disabled",
value: "disabled"
},
{
displayName: "Enabled",
value: "enabled"
}
]
};
}
onSelectOption = selected => {
this.props.onSelect(this.props.switchName, selected);
};
render() {
const { options } = this.state;
const { selected } = this.props;
return (
<MultiToggle
options={options}
selectedOption={selected}
onSelectOption={this.onSelectOption}
/>
);
}
}
家长设置
import MultiToggle from "react-multi-toggle";
import React from "react";
import "react-multi-toggle/style.css";
export default class ParentSwitch extends React.Component {
constructor(props) {
super(props);
this.state = {
options: [
{
displayName: "Disabled",
value: "disabled"
},
{
displayName: "Pending",
value: "pending"
},
{
displayName: "Enabled",
value: "enabled"
}
]
};
}
render() {
const { options } = this.state;
return (
<MultiToggle
options={options}
selectedOption={this.props.parentSwitch}
onSelectOption={() => {}}
/>
);
}
}
最佳答案
我建议您将您的 child 和家长分组在一个组件下。假设我们将其命名为Settings
。然后,我们创建另一个组件,它将呈现设置列表和一个按钮。最后一个组件将保存所有设置的值。最后,每次设置组件的值发生变化
时,我们都会更新列表。查看 sample working app here .
应用程序组件
export default class App extends PureComponent {
state = {};
onSettingChange = (settingId, setting) => {
this.setState(prevState => ({
...prevState,
[settingId]: setting
}));
};
onGetSettingValues = () => {
console.log(this.state);
};
render() {
return (
<Fragment>
<Setting id="setting1" onChange={this.onSettingChange} />
<Setting id="setting2" onChange={this.onSettingChange} />
<button onClick={this.onGetSettingValues}>Get All Values</button>
</Fragment>
);
}
}
设置组件
import React, { PureComponent, Fragment } from "react";
import ChildSwitch from "./ChildSwitch";
import ParentSwitch from "./ParentSwitch";
export default class Setting extends PureComponent {
state = {
parentVal: "disabled",
switch1Val: "enabled",
switch2Val: "disabled"
};
componentDidMount() {
this.setParentSwitchValue();
}
setChildSwitchValue = (whichSwitch, selected) => {
this.setState(
prevState => ({ ...prevState, [whichSwitch]: selected }),
this.setParentSwitchValue
);
};
handleChange = () => {
const { id, onChange } = this.props;
onChange(id, this.state);
};
setParentSwitchValue = () => {
const { switch1Val, switch2Val } = this.state;
const switchStates = [switch1Val, switch2Val];
let parent = "pending";
if (switchStates.every(val => val === "enabled")) {
parent = "enabled";
}
if (switchStates.every(val => val === "disabled")) {
parent = "disabled";
}
this.setState(
prevState => ({ ...prevState, parentVal: parent }),
this.handleChange
);
};
render() {
const { parentVal, switch1Val, switch2Val } = this.state;
return (
<Fragment>
<div className="boxed">
Parent Setting 1
<ParentSwitch
parentSwitch={parentVal}
onSelect={this.setParentSwitchValue}
/>
Setting 1:
<ChildSwitch
switchName={"switch1Val"}
selected={switch1Val}
onSelect={this.setChildSwitchValue}
/>
Setting 2:
<ChildSwitch
switchName={"switch2Val"}
selected={switch2Val}
onSelect={this.setChildSwitchValue}
/>
</div>
</Fragment>
);
}
}
关于javascript - 以父组件内对象的形式从所有子组件获取合并数据 : React JS,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57546099/