我想重新制作并排序一个数组。 是否可以使用“reduce”代替“forEach”或“map”? return beeProps.valueInfos.reduce (reduce()) 会很棒。
[Date,Onject] ---> [Number,Object] ---我想将相同的“Number”对象收集到一个数组中 ---> [Number ,Object[]]
我相信这里的人都很聪明...有人能找到好方法。
//Sample IO
type Info = {
title: string;
InfoMap: Map<Date, Slot>;
};
type Slot =
| {
kind: "on";
}
| {
kind: "off";
};
let date1 = new Date(1999, 11, 31, 20);
let date2 = new Date(1999, 11, 31, 21);
let date3 = new Date(1999, 11, 31, 22);
let date4 = new Date(1999, 11, 31, 23);
const sampleInfoDetailMap:Map<Date, Slot> = new Map();
sampleInfoDetailMap.set(date1,{kind: 'on' as const})
sampleInfoDetailMap.set(date2,{kind: 'on' as const})
sampleInfoDetailMap.set(date3,{kind: 'off' as const})
sampleInfoDetailMap.set(date4,{kind: 'on' as const})
const sampleInfoDetailMap2:Map<Date, Slot> = new Map();
sampleInfoDetailMap2.set(date1,{kind: 'on' as const})
sampleInfoDetailMap2.set(date2,{kind: 'off' as const})
sampleInfoDetailMap2.set(date3,{kind: 'off' as const})
sampleInfoDetailMap2.set(date4,{kind: 'on' as const})
console.log(date1.getTime());
console.log(date2.getTime());
let sampleInfo:Info = {title:"test1" ,InfoMap:sampleInfoDetailMap}
let sampleInfo2:Info = {title:"test2" ,InfoMap:sampleInfoDetailMap2}
let info:Info[] = new Array();
//ideal Output is
//numer => Date.getTime() : number;
//Map<number,Slot[]>
const idealResult:Map<number,Slot[]> = new Map();
//[946638000000 , [on,on]
//[946641600000 , [on,off]
//note: 946638000000 is 1999, 11, 31, 20. 946641600000 is 1999, 11, 31, 21
最佳答案
我无法从你的问题中确切地看出你在寻找什么,因为示例代码似乎没有指定特定的输入和输出。让我知道以下内容是否适合您:
const mapKeyMaps = <KI, KO, V>(
keyMapper: (ki: KI) => KO,
...inputMaps: Map<KI, V>[]
): Map<KO, V[]> =>
([] as Array<[KI, V]>).concat(...inputMaps.map(m => Array.from(m.entries())))
.map(([ki, v]) => [keyMapper(ki), v] as const)
.reduce(
(acc, [ko, v]) => ((acc.get(ko) || (acc.set(ko, []), acc.get(ko)!)).push(v), acc),
new Map<KO, V[]>()
);
它会为您的示例生成以下输出:
let info: Info[] = [sampleInfo, sampleInfo2];
const idealResult = mapKeyMaps((date) => date.getTime(), ...info.map(i => i.InfoMap))
console.log(JSON.stringify(Array.from(idealResult.entries())));
/*
[
[946688400000,[{"kind":"on"},{"kind":"on"}]],
[946692000000,[{"kind":"on"},{"kind":"off"}]],
[946695600000,[{"kind":"off"},{"kind":"off"}]],
[946699200000,[{"kind":"on"},{"kind":"on"}]]
]
*/
如果这对您有用,我将解释 mapKeyMaps()
的工作原理。如果没有,请编辑问题中的代码以构成 minimal reproducible example也许我可以提供更好的解决方案。不管怎样,祝你好运!
关于javascript - 有没有有效的方法将数据设置到MapObject?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59306450/