我有 2 个数组:
数组一:
[
{
"value": {
"_id": "5ce3f8cc35ad1e0999ee18d1",
"is_default": false,
"is_required": true,
"sort_order": 0,
"value": "",
"label": "No 38",
"option_id": "5ce3f8cc35ad1e0999ee18d0",
"__v": 0,
"selected": true
}
},
{
"value": {
"label": "Τρικολορ",
"sort_order": 0,
"value": "#7a3131|#0e8e76|#b6edd9",
"_id": "3aa5b2d7-cb78-44ce-bb5d-e4d42ebf3309",
"selected": true
}
},
{
"value": {
"label": "ΧΛ",
"sort_order": 0,
"value": "",
"_id": "5df37c50854df50b274d7829",
"selected": true
}
}
]
数组二:
[
{
"_id": "5df384edba99411550e4e019",
"options": [
{
"option": {
"sort_order": 0,
"display_name": "Μέγεθος (EU)",
"type": "text",
"display_style": "dropdown"
},
"value": {
"_id": "5ce3f8cc35ad1e0999ee18d1",
"is_default": false,
"is_required": true,
"sort_order": 0,
"value": "",
"label": "No 38",
"option_id": "5ce3f8cc35ad1e0999ee18d0",
"__v": 0
}
},
{
"option": {
"display_name": "swatch",
"display_style": "swatch",
"sort_order": 0,
"type": "swatch"
},
"value": {
"label": "Τρικολορ",
"sort_order": 0,
"value": "#7a3131|#0e8e76|#b6edd9",
"_id": "3aa5b2d7-cb78-44ce-bb5d-e4d42ebf3309"
}
},
{
"option": {
"display_name": "dropdown",
"display_style": "dropdown",
"sort_order": 0,
"type": "multiplechoice"
},
"value": {
"_id": "5df37c61854df50b274d782a",
"is_default": false,
"is_required": true,
"label": "Λ",
"sort_order": 0,
"value": "",
"value_data": null
}
}
]
},
{
"_id": "5ce3f8cc35ad1e0999ee18d1",
"options": [
{
"option": {
"sort_order": 0,
"display_name": "Μέγεθος (EU)",
"type": "text",
"display_style": "dropdown"
},
"value": {
"_id": "5ce3f8cc35ad1e0999ee18d1",
"is_default": false,
"is_required": true,
"sort_order": 0,
"value": "",
"label": "No 38",
"option_id": "5ce3f8cc35ad1e0999ee18d0",
"__v": 0
}
},
{
"option": {
"display_name": "swatch",
"display_style": "swatch",
"sort_order": 0,
"type": "swatch"
},
"value": {
"label": "Τρικολορ",
"sort_order": 0,
"value": "#7a3131|#0e8e76|#b6edd9",
"_id": "3aa5b2d7-cb78-44ce-bb5d-e4d42ebf3309"
}
},
{
"option": {
"display_name": "dropdown",
"display_style": "dropdown",
"sort_order": 0,
"type": "multiplechoice"
},
"value": {
"label": "ΧΛ",
"sort_order": 0,
"value": "",
"_id": "5df37c50854df50b274d7829"
}
}
]
}
]
如您所见，每个value _id来自 Array Two 中索引 1 处的元素匹配每个 value _id来自Array One .
如何迭代 Array Two并提取 _id如果所有元素value _id的比赛 Array One ？
我尝试了很多方法，但似乎都不起作用，例如:
const opts = newTempProduct.variants.map((item) => item.options);
const props = ['_id'];
const result = opts
.filter((o1, i) => {
o1.filter((o3) => {
return tmpVariant.some((o2) => {
return o3.value._id === o2.value._id;
});
});
})
.map(function(o) {
return props.reduce((newo, name) => {
newo[name] = o[name];
return newo;
}, {});
});
最佳答案
您可以创建一个名为 search 的附加数组。该数组是第一个数组的映射版本，仅包含 _id 属性。为了提高效率，您可以将此数组设置为 Set，这样您就可以进行 O(1) 查找。然后，您可以将 .every() 与 .filter() 一起使用，如果 options 中的所有 id 都返回 true给定对象的数组位于 search 数组中。这将为您提供最终的 ID:
const arr = [{ "value": { "_id": "5ce3f8cc35ad1e0999ee18d1", "is_default": false, "is_required": true, "sort_order": 0, "value": "", "label": "No 38", "option_id": "5ce3f8cc35ad1e0999ee18d0", "__v": 0, "selected": true } }, { "value": { "label": "Τρικολορ", "sort_order": 0, "value": "#7a3131|#0e8e76|#b6edd9", "_id": "3aa5b2d7-cb78-44ce-bb5d-e4d42ebf3309", "selected": true } }, { "value": { "label": "ΧΛ", "sort_order": 0, "value": "", "_id": "5df37c50854df50b274d7829", "selected": true } } ];
const data = [{ "_id": "5df384edba99411550e4e019", "options": [{ "option": { "sort_order": 0, "display_name": "Μέγεθος (EU)", "type": "text", "display_style": "dropdown" }, "value": { "_id": "5ce3f8cc35ad1e0999ee18d1", "is_default": false, "is_required": true, "sort_order": 0, "value": "", "label": "No 38", "option_id": "5ce3f8cc35ad1e0999ee18d0", "__v": 0 } }, { "option": { "display_name": "swatch", "display_style": "swatch", "sort_order": 0, "type": "swatch" }, "value": { "label": "Τρικολορ", "sort_order": 0, "value": "#7a3131|#0e8e76|#b6edd9", "_id": "3aa5b2d7-cb78-44ce-bb5d-e4d42ebf3309" } }, { "option": { "display_name": "dropdown", "display_style": "dropdown", "sort_order": 0, "type": "multiplechoice" }, "value": { "_id": "5df37c61854df50b274d782a", "is_default": false, "is_required": true, "label": "Λ", "sort_order": 0, "value": "", "value_data": null } } ] }, { "_id": "5ce3f8cc35ad1e0999ee18d1", "options": [{ "option": { "sort_order": 0, "display_name": "Μέγεθος (EU)", "type": "text", "display_style": "dropdown" }, "value": { "_id": "5ce3f8cc35ad1e0999ee18d1", "is_default": false, "is_required": true, "sort_order": 0, "value": "", "label": "No 38", "option_id": "5ce3f8cc35ad1e0999ee18d0", "__v": 0 } }, { "option": { "display_name": "swatch", "display_style": "swatch", "sort_order": 0, "type": "swatch" }, "value": { "label": "Τρικολορ", "sort_order": 0, "value": "#7a3131|#0e8e76|#b6edd9", "_id": "3aa5b2d7-cb78-44ce-bb5d-e4d42ebf3309" } }, { "option": { "display_name": "dropdown", "display_style": "dropdown", "sort_order": 0, "type": "multiplechoice" }, "value": { "label": "ΧΛ", "sort_order": 0, "value": "", "_id": "5df37c50854df50b274d7829" } } ] } ];
const search = new Set(arr.map(({value: {_id}}) => _id));
const res = data.filter(
({options}) => options.every(({value: {_id}}) => search.has(_id))
).map(({_id}) => _id); // use `.filter()` incase many objects match ur first array
console.log(res); // array of all _ids matched
console.log(res.pop()); // your expected/wanted result关于javascript - 通过 _id 匹配并提取两个对象数组之间的元素，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/59323941/