javascript - Firebase 函数。httpsCallable(...).then 不是函数

Question

我正在尝试使用我制作的函数。所以在我的客户端中我这样做:

const functions = firebase.app().functions("europe-west1");

        functions.httpsCallable('getSelf').then(res => {
            console.log(res);
            //stuff
        }).catch(e => {
            console.log(e);
            switch (e.code) {
                //stuff
            }
        })

基本上我得到的错误是functions.httpsCallable(...).then不是一个函数。我不太明白，也没有找到任何文档如何在不同版本的客户端上进行函数调用。

这是我的服务器端

// Gets things like adminlevel, profilepic etc
exports.getSelf = functions.region("europe-west1").https.onCall((data, context) => {
  // Checking that the user is authenticated.
  if (!context.auth) 
    // Throwing an HttpsError so that the client gets the error details.
    throw new functions.https.HttpsError('unauthorized', 'The function must be called ' +
        'while authenticated.');

  return db.collection("userInformation").doc(context.auth.uid).then(user => {
    if(!user)
      new functions.https.HttpsError('not-found', 'The user was not found');
    //returns needing values
    return {
      profilePicture: user.profilePicture,
      adminLevel: user.adminLevel,
      stripeAccountId: user.stripeAccountId,
      stripeCustomerId: user.stripeCustomerId,
      type: user.type
    }
  })
});

Answer 1

HttpsCallable本身就是一个可以带参数调用的函数，你需要在其中添加另一个():

const getSelf = functions.httpsCallable('getSelf');
getSelf({}).then(...);