javascript - 通过JavaScript修改Json数据创建新对象

Question

我有一个json数据如下

{
  "file1": {
    "function1": {
      "calls": {
        "439:0": [
          "441:24"
        ],
        "441:24": [
          "443:4"
        ],
        "443:4": [
          "447:7",
          "445:10"
        ],
        "445:10": [
          "449:4"
        ],
        "447:7": [
          "449:4"
        ]
      }
    },
    "function2": {
      "calls": {
        "391:0": [
          "393:8"
        ],
        "393:8": [
          "397:7"
        ],
        "397:7": [
          "395:27"
        ]
      }
    },
    "function3": {
      "calls": null
    },
    "function4": {
      "calls": null
    }
  },
  "file2": {
    "function5": {
      "calls": null
    },
    "function6": {
      "calls": {
        "391:0": [
          "393:8"
        ],
        "393:8": [
          "397:7"
        ],
        "397:7": [
          "395:27"
        ]
      }
    }
  }
}

我需要将其转换为“function1”的格式

    {
  "nodes": [
    {
      "id": "439:0",
      "line": "439:0"
    },
    {
      "id": "441:24",
      "line": "441:24"
    },
    {
      "id": "443:4",
      "line": "443:4"
    },
    {
      "id": "447:7",
      "line": "447:7"
    },
    {
      "id": "445:10",
      "line": "445:10"
    },
    {
      "id": "449:4",
      "line": "449:4"
    }
  ],
  "links": [
    {
      "source": "439:0",
      "target": "441:24"
    },
    {
      "source": "441:24",
      "target": "443:4"
    },
    {
      "source": "443:4",
      "target": "447:7"
    },
    {
      "source": "443:4",
      "target": "445:10"
    },
    {
      "source": "445:10",
      "target": "449:4"
    },
    {
      "source": "447:7",
      "target": "449:4"
    }
  ]
}

其中“调用”键是“节点”中的行和 id，以及“链接”中的源。目标是调用内的值。如果任何键有多个值，而不是每个值，它将创建一个源-目标对。

这将在稍后用作 data.nodes.map(function(d){return d.line})

我尝试了以下代码，但它无法正常工作。它提供了一个包含正确信息的数组，但我需要在进一步的步骤中使用它的方式，它在那里不起作用。它给出诸如属性“nodes”在类型“any[]”上不存在之类的错误。

let res = {}
let nodes = []
let links = []
Object.entries(input0).map(([fileName, fileObject]) => {
  Object.entries(fileObject).map(([functionName, functionObject]) => {
    if(functionName=="function1"){
      Object.entries(functionObject).map(([functionKey, functionValue]) => { 
        if(functionKey === "calls") {
          if(functionValue != null){
            Object.entries(functionValue).map(([callKey, callObject]) => {     
              nodes = [...nodes,{"id": callKey, "line": callKey}] 
              callObject.forEach(x => {
                links = [...links,{"source": callKey, "target": x}] 
              });
              res = {"nodes": nodes, "links": links} //nodes.concat(links)
            })                     
          }
        }
      })
    }
  })
})
console.log(res)

请有人帮忙。感谢您抽出时间。

Answer 1

您可以省略不需要的属性并直接嵌套一次，并通过检查现有节点构建一组新的节点并分配所有链接而无需进一步检查。

function getNodesLinks(object, result = { nodes: [], links: [] }) {
    if (object.calls === null) return result;
    if (!object.calls) {
        Object.values(object).forEach(v => getNodesLinks(v, result));
        return result;
    }
    Object.entries(object.calls).forEach(([source, targets]) => {
        if (!result.nodes.some(({ id }) => id === source)) {
            result.nodes.push({ id: source, line: source });
        }
        targets.forEach(target => {
            if (!result.nodes.some(({ id }) => id === target)) {
                result.nodes.push({ id: target, line: target });
            }
            result.links.push({ source, target });
        });
    });
    return result;
}

var data = { file1: { function1: { calls: { "439:0": ["441:24"], "441:24": ["443:4"], "443:4": ["447:7", "445:10"], "445:10": ["449:4"], "447:7": ["449:4"] } }, function2: { calls: { "391:0": ["393:8"], "393:8": ["397:7"], "397:7": ["395:27"] } }, function3: { calls: null }, function4: { calls: null } }, file2: { function5: { calls: null }, function6: { calls: { "391:0": ["393:8"], "393:8": ["397:7"], "397:7": ["395:27"] } } } },
    result = getNodesLinks(data);

console.log(result);

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