我设法显示某些值，但无法管理 Blade 表中的另一个值...我想显示值
description
在里面
irel__com_access_level
来 self 的 json 响应
...这是我的响应 json 和代码
{
"ID": "cust1",
"PWD": "W6ph5Mm5Pz8GgiULbPgzG37mj9g=",
"NICK_NAME": "CUST1",
"PWD_INVALID_HIT": "0",
"PWD_CREATE_DT": "2019/07/22 15:57:15",
"INSTITUTION_ID": "C01",
"ACL_ID": "L04",
"LOGIN_DT": "2019/07/22 15:57:15",
"LOGIN_STS_ID": "N",
"STS_ID": "C08",
"TYPE_ID": "U00",
"UPD_DT": "2019/07/22 15:57:15",
"EMAIL_ID": "cust1@gmail.com",
"PHONE_NO_ID": "0",
"HP_ID": "0 ",
"CRT_DATE_DELETED": null,
"irel__com_access_level": {
"ID": "L04",
"DESCRIPTION": "CUSTOMER", // i want to display this
"IS_CREATE": "Y",
"IS_READ": "Y",
"IS_UPDATE": "Y",
"IS_DELETE": "N",
"STS_ID": "R01",
"UPD_ID": "shukrimb",
"UPD_DT": "2018/06/26 11:15:10"
},
},
在我的 Controller 中
public function index()
{
$response = $this->client->get('getUserIndex')->getBody();
$content = json_decode($response->getContents());
return view('configuration.comuserprofiles.ComUserProfilesList', ['content' => $content->data]);
}
我的 Blade 文件
@foreach($content as $i=>$user)
@php
$currentRecordno = 1;
@endphp
<tr>
<td>{{ $currentRecordno + $i }}</td>
<td>{{ $user->ID }}</td>
<td>{{ $user->NICK_NAME }}</td>
<td>{{ $user->PWD_INVALID_HIT }}</td>
<td>{{ $user->???? }} </td>
最佳答案
在您的 Controller 中执行以下操作:
public function index()
{
$response = $this->client->get('getUserIndex')->getBody();
$content = json_decode($response->getContents(), true); //true convert your JSON to array
return view('configuration.comuserprofiles.ComUserProfilesList', ['content' => $content->data]);
}
然后在您的Blade中，您可以通过以下方式达到此目的:
$user['irel__com_access_level']['DESCRIPTION']
关于javascript - 如何在 laravel TableView Blade 中显示 JSON 中的指定对象值，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/60258795/