javascript - Typescript:仅当某些字段相等时才获取重复对象

Question

因此，如果对象相等，就会有很多答案。但就我而言，仅当某些字段相等时我才希望返回，并且我无法找到任何答案。

假设我有这个对象数组:

let obj = [
  { name: 'bob', adress: 'somewhere1', country: 'sweden', nr: '1235'},
  { name: 'bob', adress: 'somewhere1', country: 'norway', nr: '7656'},
  { name: 'john', adress: 'somewhere2', country: 'denmark', nr: '54534'},
  { name: 'john', adress: 'somewhere2', country: 'US', nr: '3333'},
  { name: 'steven', adress: 'somewhere3', country: 'UK', nr: '5467'}
]

我想按名称和地址过滤它们(如果它们相等)，将它们添加到新数组中:

let newObj = [
  [{
      name: 'bob',
      adress: 'somewhere1',
      country: 'sweden',
      nr: '1235'
    },
    {
      name: 'bob',
      adress: 'somewhere1',
      country: 'norway',
      nr: '7656'
    }
  ],
  [{
      name: 'john',
      adress: 'somewhere2',
      country: 'denmark',
      nr: '54534'
    },
    {
      name: 'john',
      adress: 'somewhere2',
      country: 'US',
      nr: '3333'
    }
  ],
  [{
    name: 'steven',
    adress: 'somewhere3',
    country: 'UK',
    nr: '5467'
  }]
]

Answer 1

const arr = [
  { name: 'bob', address: 'somewhere1', country: 'sweden', nr: '1235'},
  { name: 'bob', address: 'somewhere1', country: 'norway', nr: '7656'},
  { name: 'john', address: 'somewhere2', country: 'denmark', nr: '54534'},
  { name: 'john', address: 'somewhere2', country: 'US', nr: '3333'},
  { name: 'steven', address: 'somewhere3', country: 'UK', nr: '5467'}
];

const grouped = Object.values(arr.reduce((accum, item) => {
  const nameAndAddress = `${item.name}${item.address}`;
  if (!accum[nameAndAddress]) accum[nameAndAddress] = [];
  accum[nameAndAddress].push(item);
  return accum;
}, {}));

这将使用组合的名称和地址作为唯一标识符，并将记录分离到该标识符上的数组中，然后将这些数组从结果对象中拉出到所需输出中的数组中。