javascript - 从代码隐藏打开的弹出窗口未关闭

Question

我正在从代码后面打开一个弹出窗口(我在处理时将其用作等待图像)，之后我在后台进行一些事件，当事件完成时，我将关闭该弹出窗口。问题是事件结束后弹出窗口没有关闭。我做错了什么，这是我的代码片段:-

    System.Text.StringBuilder sb = new System.Text.StringBuilder();
            sb.Append("<script language='javascript'>");
            sb.Append("var win=");
            sb.Append("window.open('WaitingImage.aspx', 'Wait',");
            sb.Append("'width=800, height=600, menubar=no, resizable=no');window.focus();<");
            sb.Append("/script>");

            Type t = this.GetType();
            if (!ClientScript.IsClientScriptBlockRegistered(t, "PopupScript"))
            {
            ClientScript.RegisterClientScriptBlock(t,"PopupScript", sb.ToString());
            }
        //pop up opened.. now do the processing :-
             uploadFiles();
        //now close the pop up after work is done:-

        System.Text.StringBuilder sbs = new System.Text.StringBuilder();
        sbs.Append("<script language='javascript'>");
        sbs.Append("window.close()");
        sbs.Append("/script>");
        Type tr = this.GetType();
        ClientScript.RegisterClientScriptBlock(tr, "PopupScript", sbs.ToString());

Answer 1

您将弹出窗口分配给 win 变量，但是当您关闭时，您调用 window.close...

尝试改变

 sbs.Append("window.close()");

至

 sbs.Append("win.close()");