我正在尝试在 JS 文件和 PHP 文件之间传递数据，但 PHP 中的变量 $_POST 不起作用，因此我无法在应用程序中进化!
JS代码:
var params = String(input.value);
var xhr = Titanium.Network.createHTTPClient();
xhr.open('GET','http://10.0.2.2/jobfinder/teste_demo_grafica/Resources/teste.php');
xhr.send(params);
xhr.onload = function(){
var response = this.responseText;
alert(response);
if (response != null)
{
alert("voltou ao js e funca");
}
else
{
alert("-.-");
}
};
xhr.setRequestHeader("Content-Type","application/x-www-form-urlencoded");
xhr.onerror = function(e){alert('Transmission error: ' + e.error);};
});
现在是 php 代码:
<?php
// Connect to the database(host, username, password)
$con = mysql_connect('localhost','root','');
if (!$con)
{
return ("Failed to make connection.");
exit;
}
// Select the database. Enter the name of your database (not the same as the table name)
$db = mysql_select_db('jobfinder');
if (!$db)
{
echo "Failed to select db.";
exit;
}
$pesquisa= $_POST[params];
echo "pesquisa";
$sql = "SELECT * FROM oferta WHERE titulo like '%$pesquisa%'";
$query = mysql_query($sql);
if (mysql_num_rows($query) > 0)
{
$row = mysql_fetch_array($query);
$response = array(
'titulo' => $row['titulo'],
'oferta' => $row['descricao_oferta']
);
json_encode($response);
echo $response['titulo'];
}
else
{
// Else the username and/or password was invalid! Create an array, json_encode it and echo it out
$response = array(
'message' => 'Não existem ofertas para esta pesquisa'
);
json_encode($response);
}
echo "php mode off";
?>
最佳答案
据猜测，您的 JavaScript 正在通过 GET 发送数据:
xhr.open('GET','http://10.0.2.2/jobfinder/teste_demo_grafica/Resources/teste.php');
但是你的 PHP 正在寻找 POST。将 POST 更改为 GET 可能会起作用。反之亦然
关于php - $_POST 变量在 php Titanium 中不起作用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/10171202/