javascript - 从数组动态构建表

Question

我已经尝试让这段代码工作几个小时了，似乎无法弄清楚我做错了什么或者我可能搞砸了什么，我从一个有效的示例页面复制了这段代码并修改它以制作我想要构建的表..

原始剪辑代码:

$(function () {
            var $wrap = $('<div>').attr('id', 'tableWrap');
            var $tbl = $('<table>').attr('id', 'basicTable');

            for (var i = 0; i < 200; i++) {
                $tbl.append($('<tr>').append($('<td>').text(i),$('<td>').text(200 - i)));
            }

            $wrap.append($tbl);
            $('body').append($wrap);
        });

现在我将其更改为六行，并从 javascript 数组加载链接和数据，但由于某种原因，它不会构建表格..

我的代码:

myArray = new Array();
    myArray[0] = new Array("001","Title","http://www.google.com/","https://www.google.com/images/logos/google_logo_41.png");
    myArray[1] = new Array("002","Title","http://www.google.com/","https://www.google.com/images/logos/google_logo_41.png");
    myArray[2] = new Array("003","Title","http://www.google.com/","https://www.google.com/images/logos/google_logo_41.png");
    myArray[3] = new Array("004","Title","http://www.google.com/","https://www.google.com/images/logos/google_logo_41.png");
    myArray[4] = new Array("005","Title","http://www.google.com/","https://www.google.com/images/logos/google_logo_41.png");
    myArray[5] = new Array("006","Title","http://www.google.com/","https://www.google.com/images/logos/google_logo_41.png");
    myArray[6] = new Array("007","Title","http://www.google.com/","https://www.google.com/images/logos/google_logo_41.png");
    myArray[7] = new Array("008","Title","http://www.google.com/","https://www.google.com/images/logos/google_logo_41.png");
    myArray[8] = new Array("009","Title","http://www.google.com/","https://www.google.com/images/logos/google_logo_41.png");
    myArray[9] = new Array("010","Title","http://www.google.com/","https://www.google.com/images/logos/google_logo_41.png");


    var $wrap = $('<div>').attr('id', 'tableWrap');              
    var $tbl = $('<table>').attr('id', 'basicTable'); 

    for(i=0;i<myArray.length;i++){
        $(function () {                                   
            $tbl.append($('<tr>').append(
                        $('<td>').text('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]'"></a>'),
                        $('<td>').text('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]'"></a>'),
                        $('<td>').text('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]'"></a>'),
                        $('<td>').text('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]'"></a>'),
                        $('<td>').text('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]'"></a>'),
                        $('<td>').text('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]'"></a>')));             
        }              
        $wrap.append($tbl);             
        $('#c').append($wrap);         
    });

我的 body 里有一个..

 <div id="c"></div>

我正在尝试将其加载到...我想坚持使用 jquery，但几乎想只使用 javascript document.write 函数

---- 更新 05/14/2012 ----
感谢许多人的帮助，现在只能使用 JavaScript。让它按照我现在需要的方式工作，直到我度假回来。我仍然想将它压缩/转换为 jquery，这样它看起来更干净并且已经将它用于其他事情。因此，对于任何读过这篇文章并且正在寻找这个方向的人来说，这里是 jsFiddle我折腾在一起，以帮助展示我如何在大家的帮助下进行设置......再次感谢大家!!

Answer 1

$(function () {      
    var $wrap = $('<div/>').attr('id', 'tableWrap');              
    var $tbl = $('<table/>').attr('id', 'basicTable');

    for(i=0;i<myArray.length;i++){
            //  $(function () { is miss placed                     
            $tbl.append($('<tr/>').append(
                        $('<td/>').html('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]+'"></a>'),
                        $('<td/>').html('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]+'"></a>'),
                        $('<td/>').html('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]+'"></a>'),
                        $('<td/>').html('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]+'"></a>'),
                        $('<td/>').html('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]+'"></a>'),
                        $('<td/>').html('<a href="'+myArray[i][2]+'" target="_new"><img src="'+myArray[i][3]+'" alt="'+myArray[i][1]+'"></a>')));             
        }              
        $wrap.append($tbl);             
        $('#c').append($wrap);         
    });

问题

1. 缺少 $(function) {..
的位置
2. alt="'+myArray[i][1]'" 应为 alt="'+myArray[i][1]+'"<

<强> DEMO